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pishuonlain [190]
3 years ago
11

The initial temperature of a 1.00 liter sample of argon is 20 Celsius. The pressure is decreased from 720 mm Hg to 360 mm Hg and

the volume increases to 2.14 liters. What is the final temperature of the argon?
Chemistry
1 answer:
Rasek [7]3 years ago
4 0

Answer:314k

Explanation:

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Consider a 0.12 M solution of a weak polyprotic acid (H2A) with the possible values of Ka1 and Ka2 given here. Calculate the con
tatuchka [14]

The  [H3O+] in step 1 is 0.0034 M while the  [H3O+] in step 2 is 0.00039 M

<h3>What is the contribution of each  step?</h3>

Let us set up the ICE table in each case, for K1;

         H2A(aq) + H2O(l)-------->   H3O^+(aq) + HA^-(aq)

I        0.12                                     0                    0

C       -x                                        +x                   +x

E      0.12 - x                                x                     x

Ka1= [H3O^+] [HA^-]/[ H2A]

Ka1= x^2/  0.12 - x  

1.0×10^−4 = x^2/  0.12 - x  

1.0×10^−4(0.12 - x ) = x^2

1.2 * 10^-5 - 1.0×10^−4x =  x^2

x^2 +  1.0×10^−4x - 1.2 * 10^-5  = 0

x =0.0034 M

[H3O+] = 0.0034 M

Again;  [H3O+] = [HA^-] = 0.0034 M

          HA^-(aq) + H20(l)    -------> A^-(aq)   + H3O^+

I       0.0034                                  0               0

C       -x                                          + x            +x

E    0.0034 - x                               x                x

Ka2= [A^-] [H3O^+]/[HA^-]

5.0×10^−5 = x^2/ 0.0034 - x  

5.0×10^−5 (0.0034 - x ) = x^2

1.7 * 10^-7 - 5.0×10^−5x =  x^2

x^2 + 5.0×10^−5x - 1.7 * 10^-7 = 0

x=0.00039 M

Learn more about the dissociation of a polyprotic acid:brainly.com/question/14481763

#SPJ1

7 0
1 year ago
Define the following terms<br><br> Uniformitarianism<br><br> &amp; <br><br> trace fossil
AnnZ [28]

Answer:

Uniformitarianism- A theory that geologic process that occur today are similar to those that have occurred in the past

Trace Fossil- A fossil of a foot or trail or other travel of an animal rather than of the animal itself

4 0
3 years ago
Read 2 more answers
5<br> - HCN +<br> CuSO4 →<br> Type of reaction
lesya692 [45]

Answer:

CuSO_{4}+2HCN\rightarrow Cu(CN)_{2}+H_{2}SO_{4}

Explanation:

The valancy of Cu = +2

SO4 = -2

CN = -1

H =+1

So when HCN and CuSO4 react Cu(CN)2 and H2SO4 are formed.

Cu(CN)2 formation :

2 CN = 2 x -1  = -2

Its should attach to +2 charge atom which is Cu

So 1 Cu and 2 CN = Cu(CN)2

Similary,

H2SO4 formation:

SO4 = -2 charge

It require +2 charge so need two H+

2 H = 2x1 = +2 charge

Hence , 1 SO4 and 2 H combine to form H2SO4

<u><em>Law of conservation of mass:</em></u><em> It states that mass can neither be created nor destroyed during a chemical reaction.</em>

<em>Total mass of the reactant must be equal to total mass of product.</em>

<u>Only those equations are balanced which follows law of conservation of mass </u>

Count total number of atoms in the reactant and product .

The number of atoms in the product = The number of atoms in the reactant

In the given equation:

CuSO_{4}+2HCN\rightarrow Cu(CN)_{2}+H_{2}SO_{4}

Reactant are 2HCN and CuSO4

atoms of H = 1x2=2 , C=1x2=2  , N=1x2=2 , Cu = 1, S = 1 ,O =4

Products: Cu(CN)2 and H2SO4

atoms of H =2 , S=1 , O=4 ,C = 2x1=2 , N = 2x1 =2 , Cu = 1

Hence this is balance equation

7 0
3 years ago
An element's atomic number is 7. How many protons would an atom of this element have?
rusak2 [61]

well the atomic number is 7 the number of protons is also equal to 7 .

hope this helps


8 0
3 years ago
Read 2 more answers
HELP 80 points
Triss [41]

243.92J

Explanation:

Given parameters:

Mass of the aluminum cup = 42.14g

Initial temperature of the cup, t₁ = 20°C

Final temperature of the cup t₂ = 26.41°C

Specific heat capacity of aluminium = 0.903 J g⁻¹ °C⁻¹

Unknown:

Change in heat of the aluminium cup, q = ?

Solution:

The heat lost during the experiment is the heat gained by the aluminum cup.

The quantity of heat is found using the expression below:

    q = m C Δt

m is the mass of the cup

C is the specific heat of the cup

Δt is the change in heat

 q = 42.14 x 0.903 x (26.41 - 20) = 42.14 x 0.903 x 6.41

 q = 243.92J

Learn more:

Specific heat capacity brainly.com/question/7210400

#learnwithBrainly

8 0
3 years ago
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