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deff fn [24]
3 years ago
6

5 - HCN + CuSO4 → Type of reaction

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

CuSO_{4}+2HCN\rightarrow Cu(CN)_{2}+H_{2}SO_{4}

Explanation:

The valancy of Cu = +2

SO4 = -2

CN = -1

H =+1

So when HCN and CuSO4 react Cu(CN)2 and H2SO4 are formed.

Cu(CN)2 formation :

2 CN = 2 x -1  = -2

Its should attach to +2 charge atom which is Cu

So 1 Cu and 2 CN = Cu(CN)2

Similary,

H2SO4 formation:

SO4 = -2 charge

It require +2 charge so need two H+

2 H = 2x1 = +2 charge

Hence , 1 SO4 and 2 H combine to form H2SO4

<u><em>Law of conservation of mass:</em></u><em> It states that mass can neither be created nor destroyed during a chemical reaction.</em>

<em>Total mass of the reactant must be equal to total mass of product.</em>

<u>Only those equations are balanced which follows law of conservation of mass </u>

Count total number of atoms in the reactant and product .

The number of atoms in the product = The number of atoms in the reactant

In the given equation:

CuSO_{4}+2HCN\rightarrow Cu(CN)_{2}+H_{2}SO_{4}

Reactant are 2HCN and CuSO4

atoms of H = 1x2=2 , C=1x2=2  , N=1x2=2 , Cu = 1, S = 1 ,O =4

Products: Cu(CN)2 and H2SO4

atoms of H =2 , S=1 , O=4 ,C = 2x1=2 , N = 2x1 =2 , Cu = 1

Hence this is balance equation

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Answer:

The pH of a solution is simply a measure of the concentration of hydrogen ions,  

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∣

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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a

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−−−−−−−−−−−−−−−−−−−−−−−−  

Now, we use the negative log base  

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Explanation:

4 0
3 years ago
Read 2 more answers
The reaction for the formation of gaseous hydrogen fluoride (HF) from molecular hydrogen (H2) and fluorine (F2) has an equilibri
mestny [16]

Answer:

[H2]eq = 0.0129 M

[F2]eq = 1.0129 M

[HF]eq = 0.9871 M

Explanation:

  • H2(g) + F2(g) ↔ 2HF(g)

∴ Ke = [HF]² / [H2]*[F2] = 1.15 E2

experiment:

∴ n H2 = 3.00 mol

∴ n F2 = 6.00 mol

∴ V sln = 3.00 L

⇒ [H2]i = 3.00 mol / 3.00 L = 1 M

⇒ [F2]i = 6.00 mol / 3.00 L = 2 M

        [ ]i    change      [ ]eq

H2     1         1 - x         1 - x

F2     2        2 - x         2 - x

HF     -            x              x

⇒ K = (x)² / (1 - x)*(2 - x) = 1.15 E2

⇒ x² / (2 - 3x + x²) = 1.15 E2 = 115

⇒ x² = (2 - 3x + x²)(115)

⇒ x² = 230 - 345x + 115x²

⇒ 0 = 230 - 345x + 114x²

⇒ x = 0.9871

equilibrium:

⇒ [H2] = 1 - x = 1 - 0.9871 = 0.0129 M

⇒ [F2] = 2 - x = 2 - 0.9871 = 1.0129 M

⇒ [HF] = x = 0.9871 M

5 0
3 years ago
Whenever energy is ______ from one form to another, some of that energy is lost by being changed into heat.
schepotkina [342]
Whenever energy is converted from one form to another, some of that energy is lost by being changed into heat.
5 0
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VashaNatasha [74]

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2 years ago
Consider the reaction of CaCN2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How m
adelina 88 [10]

Answer:

56 g. Option 3.

Explanation:

The reaction is: CaCN₂ + 3H₂O → CaCO₃ + 2 NH₃

1 mol of calcium cianide reacts with 3 moles of water in order to produce 1 mol of calcium carbonate and 2 moles of ammonia

We have the mass of each reactant, so let's convert the mass to moles:

45 g. 1mol / 80.08 g = 0.562 moles of cianide

45 g. 1mol / 18 g = 2.5 moles of water

The cianide is the limiting reactant:

3 moles of water need 1 mol of cianide to react

Then, 2.5 moles of water will need (2.5 . 1)/ 3 = 0.833 moles

As we have 0.562 moles of CN⁻ we don't have enough

We can work now, on the reaction:

Ratio is 1:1. Therefore 0.562 moles of cianide will produce 0.562 moles of carbonate

Let's convert the mass to moles to find the answer:

0.562 mol . 100.08 g / 1 mol = 56.2 g

8 0
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