5^5=5*5*5*5*5=25*25*5=625*5=3125
There will be 15 orange pickles and 10 green picks
Answer:
1 i think
Step-by-step explanation:
hope this helps :) have a nice day :) :)
<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Answer:
$592.92
Step-by-step explanation:
Bills:
47 ones = 47*1 = $47
22 fives = 22*5 = $110
9 tens = 9*10 = $90
17 twenties = 17*20 = $340
Total Bills: 47+110+90+340 = $587
Coins:
67 pennies = 67*1 = $0.67
12 nickels = 12*5 = $0.60
9 dimes = 9*10 = $0.90
15 quaters = 15*25 = $3.75
Total Coins: 0.67+0.6+0.9+3.75 = $5.92
Total: $587+$5.92 = $592.92
