Answer:
The second one (3x, 9x)
Step-by-step explanation:
Like terms are the terms that either have the same variable or have no variable.
X = 37
150= 4x + 2
148 = 4x
X = 37
Given expression is 35, 36, 37, 38...
First term a = 35
Common difference d = 36-35 = 1
Nth term of arithmetic sequence is:
To find the 100th term, substitute n = 100
Correct option is B
Answer:
Step-by-step explanation:
We are looking for the value of x so that the function has the given value in the following:
1) h(x) = -7x; h(x)=63
From the function given above,
If h(x) = 63, then,
h(x) = 63 = -7x
-7x = 63
Dividing the left hand side and right hand side of the equation by -7, it becomes
-7x/-7 = 63/-7
x = - 9
2) m(x) = 4x + 15; m(x)=7
From the function given above,
If m(x) = 7, then,
m(x) = 7 = 4x + 15
7 = 4x + 15
4x = 15 - 7 = 8
Dividing the left hand side and right hand side of the equation by 4, it becomes
4x/4 = 8/4
x = 2
3) q(x) = 1/2x - 3; q(x) = -4
From the function given above,
If q(x) = - 4, then,
q(x) = - 4 = 1/(2x - 3) =
Cross multiplying,
-4(2x-3) = 1
-8x +12 = 1
Collecting like terms,
-8x = 1 - 12
-8x = -11
Dividing the left hand side and right hand side of the equation by -8, it becomes
-8x/8 = -11/-8
x = 11/8
Answer:
nickels = 12
quarters = 9
Step-by-step explanation:
Let number of quarters be "q", and
number of nickels be "n"
Nickels are worth $0.05 and Quarters are worth $0.25
Since all of them are worth 2.85, we can write:
0.25q + 0.05n = 2.85
Also, we know, there are 3 more nickels than quarters, so we can write:
n = 3 + q
Now, we can substitute equation 2 into equation 1 to get:
Now, we solve for q:
There are 9 quarters.
We know n = 3 + q
So,
n = 3 + 9
n = 12
There are 12 nickels
