Answer:
3.4 x 10^-4 T
Explanation:
A = 1.5 x 10^-3 m^2
N = 50
R = 180 ohm
q = 9.3 x 106-5 c
Let B be the magnetic field.
Initially the normal of coil is parallel to the magnetic field so the magnetic flux is maximum and then it is rotated by 90 degree, it means the normal of the coil makes an angle 90 degree with the magnetic field so the flux is zero .
Let e be the induced emf and i be the induced current
e = rate of change of magnetic flux
e = dФ / dt
i / R = B x A / t
i x t / ( A x R) = B
B = q / ( A x R)
B = (9.3 x 10^-5) / (1.5 x 10^-3 x 180) = 3.4 x 10^-4 T
It takes the car 14 seconds to stop
Explanation:
A car is traveling at a constant velocity of 19 m/s when the driver puts
on the brakes to accelerate it at -1.4 m/s² until stopped
1. The initial velocity is 19 m/s
2. The acceleration is -1.4 m/s²
3. The final velocity is zero
We need to find how long it takes the car to stop
We can find the time by using the rule
→ v = u + a t
where v is the final velocity, u is the initial velocity, a is the
acceleration and t is the time
→ v = 0 m/s , u = 19 m/s , a = -1.4 m/s²
Substitute these values in the rule
→ 0 = 19 + (-1.4) t
→ 0 = 19 - 1.4 t
Add 1.4 t to both sides
→ 1.4 t = 19
Divide both sides by 1.4
→ t = 13.57 ≅ 14 seconds
It takes the car 14 seconds to stop
Learn more:
You can learn more about velocity in brainly.com/question/10772739
#LearnwithBrainly
If you have ever lived in Chicago, then the answer might very well be C.
Newton's Second law states F = ma. This problem has nothing to do with acceleration.
Newton's Third law is the familiar action/reaction law. If the poles are anchored well enough and have a flexural strength greater than the tension exerted on them by the wire; then D is just.
That leaves B. There's no problem all we have to do is to increase the horizontal tension in the cable.
Answer:
No, the volume don't affect the potential energy.
Explanation:
The volume does not affect the potential energy, as this energy depends on the mass and elevation of the body relative to the reference point. This analysis can be easily seen in the equation expressing potential energy
![E_{p} =m*g*h\\where:\\m=mass[kg]\\g=gravity[m/^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cwhere%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2F%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
