<span>Mass of the block m = 3.3kg
Angle of the slide = 30 degrees
Distance the block slides s = 2.10 m
Time taken to slide t = 1.6 s
Initially in rest condition so initial velocity u = 0.
We have an equation for distance s = (u x t) + (1/2) x (a t^2)
s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56)
2.56a = 4.20 => a = 1.64
So the magnitude of the Acceleration a = 1.64 m/s^2</span>
We know that either team is winning which means that the cumulative forces (sum of each girl force) on both teams are equal.
This means,

being x the force of the fourth girl on the east team.
Solving to x, you get

The fourth girl on the east is pulling with a force of 220N.
Answer:
The amplitude of the resultant wave will be 0.
Explanation:
Suppose the first wave has an amplitude of A. Its angle is given as wt.
The second way will also have the same amplitude as that of first.
After the reflection, a phase shift of π is added So the wave is given as

Adding the two waves give

So the amplitude of the resultant wave will be 0.
Answer: -2m/s²
Explanation:
Each second, the acceleration decreases of 2m/s²
N.B.: in physics, deceleration is also acceleration.