1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
2 years ago
11

How many moles of br2(l) (mm = 159.80 g/mol) are in 13.9 ml of liquid bromine? the density of br2(l) is 3.12 g/ml?

Chemistry
1 answer:
diamong [38]2 years ago
7 0

Answer:

             Moles  =  0.271 mol

Solution:

Step 1: Calculate Mass of Br₂ as;

                               Density  =  Mass  ÷  Volume

Solving for Mass,

                               Mass  =  Density  ×  Volume

Putting values,

                               Mass  =  3.12 g.mL⁻¹  ×  13.9 mL

                               Mass  =  43.36 g

Step 2: Calculate Moles of Br₂ as;

                               Moles  =  Mass  ÷  M.Mass

Putting values,

                               Moles  =  43.36 g ÷  159.80 g.mol⁻¹

                              Moles  =  0.271 mol

You might be interested in
What is the mass of 3.62X10^24 molecules of methanol
Bad White [126]
N(CH₃OH)=3,62·10²⁴/6·10²³ 1/mol = 6,033 mol
m(CH₃OH) = 6,033 mol · 32 g/mol (molar mass) = 193,06 g.
7 0
3 years ago
Read 2 more answers
g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have
V125BC [204]

Answer:

pH = 2.66

Explanation:

  • Acetic Acid + NaOH → Sodium Acetate + H₂O

First we <u>calculate the number of moles of each reactant</u>, using the <em>given volumes and concentrations</em>:

  • 0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid
  • 1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We<u> calculate how many acetic acid moles remain after the reaction</u>:

  • 37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now <u>calculate the molar concentration of acetic acid after the reaction</u>:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we <u>calculate [H⁺]</u>, using the<em> following formula for weak acid solutions</em>:

  • [H⁺] = \sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}
  • [H⁺] = 0.0028

Finally we <u>calculate the pH</u>:

  • pH = -log[H⁺]
  • pH = 2.66
8 0
2 years ago
Which diagram shows the correct direction of electron flow in an electrolytic cell?
Alborosie

Answer:

A

Explanation:

4 0
2 years ago
Hey hiihhbdndkdkdjdjddjdj
grigory [225]

Answer:

4 cups are about 0.25 gallons

Explanation:

To convert a cup measurement to a gallon measurement, divide the volume by the conversion ratio. The volume in gallons is equal to the cups divided by 16.

7 0
2 years ago
Read 2 more answers
2.0 L of a gas is at STP. What is the new pressure in kPa if the volume changes to 10.5 L and the temperature and # of molecules
Alexandra [31]

Answer:

What is the new volume if the temperature is constant? V=2.50L. P = lookPa. P2=40k Pa. V2 = x. PV = P2 ... If a sample of gas occupies 6.8 L at 327°C

5 0
2 years ago
Other questions:
  • I need help so please help me
    12·1 answer
  • Under certain conditions neon gases diffuse at a rate of 7.0 cm/s under the same conditions as an on known gas defuses at a rate
    11·1 answer
  • Which of the following is a compound? A brass, B rust, C iron, D steel. please explain
    6·2 answers
  • Which property of a mineral sample does not influence how quickly it settles in water? 1) density 2) hardness 3) shape 4) size
    7·1 answer
  • Which of the following has the shortest bond lenght Options A). H2 B).N2 C).O2 D).F2
    11·1 answer
  • HELPPPPPPPPPPPPOOOooooooo
    6·1 answer
  • HELP ASAP ILL GIVE BRAINIEST!!!
    5·1 answer
  • Which term is de ned as the region in an atom where an electron is most likely to be located?
    7·1 answer
  • In order to prove that the Law of Conservation Mass is obeyed, what are the coefficients
    10·1 answer
  • The relation between stability and solubility​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!