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damaskus [11]
3 years ago
11

How many moles of br2(l) (mm = 159.80 g/mol) are in 13.9 ml of liquid bromine? the density of br2(l) is 3.12 g/ml?

Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer:

             Moles  =  0.271 mol

Solution:

Step 1: Calculate Mass of Br₂ as;

                               Density  =  Mass  ÷  Volume

Solving for Mass,

                               Mass  =  Density  ×  Volume

Putting values,

                               Mass  =  3.12 g.mL⁻¹  ×  13.9 mL

                               Mass  =  43.36 g

Step 2: Calculate Moles of Br₂ as;

                               Moles  =  Mass  ÷  M.Mass

Putting values,

                               Moles  =  43.36 g ÷  159.80 g.mol⁻¹

                              Moles  =  0.271 mol

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Answer:

The heat of reaction when hydrogen and oxygen combine to form water is :

<u>C. 571.6 kJ</u>

Explanation:

Enthalpy Change = The enthalpy change for the formation of 1 mole of the substance from their standard state is called the enthalpy of formation.

This is intensive quantity as it is fixed for 1 mole .

Intensive properties = Those properties which are independent on the amount of the substance are intensive properties.

The value of these quantities does not get halve if you divide the substance into two equal parts. example , density, refractive index.

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Hence for this reaction :

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