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damaskus [11]
3 years ago
11

How many moles of br2(l) (mm = 159.80 g/mol) are in 13.9 ml of liquid bromine? the density of br2(l) is 3.12 g/ml?

Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer:

             Moles  =  0.271 mol

Solution:

Step 1: Calculate Mass of Br₂ as;

                               Density  =  Mass  ÷  Volume

Solving for Mass,

                               Mass  =  Density  ×  Volume

Putting values,

                               Mass  =  3.12 g.mL⁻¹  ×  13.9 mL

                               Mass  =  43.36 g

Step 2: Calculate Moles of Br₂ as;

                               Moles  =  Mass  ÷  M.Mass

Putting values,

                               Moles  =  43.36 g ÷  159.80 g.mol⁻¹

                              Moles  =  0.271 mol

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[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

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The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

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<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

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I hope it helps you!          

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The balanced equation for given reaction is as follows ;

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Molar ratio can be determined by the coefficients of the compounds in the balanced reaction

Coefficient is the number in front of the chemical compound and they are as follows

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Learn more about mole ratio here ;

https://brainly.in/question/32799056

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