Answer:
D, because he discovered electrons
Explanation:
Interphase is not a phase of mitosis.
Answer:
![m_{HgCl_2}=42.7gHgCl_2](https://tex.z-dn.net/?f=m_%7BHgCl_2%7D%3D42.7gHgCl_2)
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
![HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4](https://tex.z-dn.net/?f=HgSO_4%2B2NaCl%5Crightarrow%20HgCl_2%2BNa_2SO_4)
In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:
![m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2](https://tex.z-dn.net/?f=m_%7BHgCl_2%7D%3D46.6gHgSO_4%2A%5Cfrac%7B1molHgSO_4%7D%7B296.65%20gHgSO_4%7D%2A%5Cfrac%7B1molHgCl_2%7D%7B1molHgSO_4%7D%20%2A%5Cfrac%7B271.52gHgCl_2%7D%7B1molHgCl_2%7D%20%5C%5C%5C%5Cm_%7BHgCl_2%7D%3D42.7gHgCl_2)
Best regards.
So really you only need to answer the first one because you have more than enough og everything. 2×(what)=14 then that will be your answer
Answer:
47.2 g
Explanation:
Let's consider the following double displacement reaction.
3 FeCl₂ + 2 Na₃PO₄ → Fe₃(PO₄)₂ + 6 NaCl
The molar mass of Fe₃(PO₄)₂ is 357.48 g/mol. The moles corresponding to 44.3 g are:
44.3 g × (1 mol / 357.48 g) = 0.124 mol
The molar ratio of Fe₃(PO₄)₂ to FeCl₂ is 1:3. The moles of FeCl₂ are:
3 × 0.124 mol = 0.372 mol
The molar mass of FeCl₂ is 126.75 g/mol. The mass of FeCl₂ is:
0.372 mol × (126.75 g/mol) = 47.2 g