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1 year ago

the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.

Chemistry

1 answer:

trapecia [35]1 year ago

8 0

The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

[Kr] 4d10 5s2 5p3

B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

[Xe] 6s1

Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

learn more about Noble gas:

brainly.com/question/2094768

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When sodium carbonate is dissolved in water, the equation is $Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$ .

When carbon dioxide is placed in water, aqueous carbon dioxide is formed: $CO_2 (g) --- > CO_2(aq)$

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Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.

Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.

While in solution, sodium carbonate dissociates into its component ions according to the following equation:

$Na_2CO_3 (s) --- > 2Na^+ (aq) + CO_3^{2-} (aq)$

Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.

Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as: $CO_2 (g) --- > CO_2(aq)$

More on the dissolution of substances can be found here: brainly.com/question/28580758

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