Answer:
Its either glucose or protien
Explanation:
MH₂: 2 g/mol
mNH₃: 17 g/mol
...............................
3H₂ + N₂ ---> 2NH₃
6g......................34g
6g H₂ ---- 34g NH₃
Xg -------- 13,09g
X = (6×13,09)/34
X = 2,31g H₂
Answer:
K = 361.369
Explanation:
C2H4(g) + H2O(g) → CH3CH2OH(g)
∴ ΔG°f(298.15K) CH3CH2OH(g) = - 174.8 KJ/mol
∴ ΔG°f(298.15) C2H4(g) = 68.4 KJ/mol
∴ ΔG°f(298.15) H2O(g) = - 228.6 KJ/mol
⇒ ΔG°f(298.15) = - 174.8 - ( - 228.6 + 68.4 ) = - 14.6 KJ/mol
∴ R = 8.314 E-3 KJ/mol.K
∴ T = 298.15 K
⇒ K = e∧(-(-14.6)/((8.314 E-3)(298.15)))
⇒ K = e∧(5.889)
⇒ K = 361.369
Hi there
My prediction is that as you put substances is that is will delay the boiling point of the water as it is heated
Also I found a answer on study.con but it requests that I do a email but I figured you may need it in the future
Answer:
Well, you'd have 1 electron more than protons (since there are 10 protons and 11 electrons). So the previously neutral ion has now become an ion with a -1 charge