Question

A research Van de Graaff generator has a 2.00-m diameter metal sphere with a charge of 5.00 mC on it.

Answer 1

Answer:

a) $V=49.5MV$

b)$r=49.5m$

c) $\Delta U=3*(49.5-1)=145.5 MeV$  

Explanation:

a) The potential equation is given by:

$V=k\frac{Q}{r}$

k is the electrostatic constant ($k=9.9*10^{9}Nm^{2}/C^{2}$)

Q is the charge Q = 5mC

r is the radius of the sphere r = 1 m

$V=9.9*10^{9}\frac{5*10^{-3}}{1}=49.5MV$

b) We solve it using the same equation.

Here we need to find r:

$r=k\frac{Q}{V}$

$r=9.9*10^{9}\frac{5*10^{-3}}{1*10^{6}}$

$r=49.5m$

c) The relation between difference potential and electrical energy is:

$\Delta U=\Delta Vq$

here q is 3e becuase oxygen atom has three missing electrons

Therefore:

$\Delta U=3*(49.5-1)=145.5 MeV$  

I hope it heps you!