Question

A peregrine falcon dives at a pigeon. The falcon starts downward from rest with free-fall acceleration. If the pigeon is 56.0 m below the initial position of the falcon, how long does the falcon take to reach the pigeon? Assume that the pigeon remains at rest.
______S

Answer 1

Answer:

3.4 s

Explanation

The first step is to write down everything we have then we can decide on the equation of linear motion to use

initial velocity = 0 m/s

acceleration = g = 9.81 m/s²

time (t)= ? that is what the question is asking.

So our equation of choice must have all these variables

$s = ut + \frac{at^{2} }{2} \\\\56 = (0)(t) + \frac{9.81*t^{2} }{2} \\\\112 = 9.81t^{2} \\\\t = 3.4 s$

Answer 2

 

The solution would be like this for this specific problem:

 

v = ? 
u = 0.0 m/s 
a = 9.8 m/s^2 
s = 56.1 m 

v^2 = (0.0 m/s)^2 + [2 * (9.8 m/s^2) * (56 m) ] 
v^2 = 2 * (9.8 m/s^2) * (56 m) 
v^2 = 1,097.6 m^2/s^2 
v = SQRT {1,097.6 m^2/s^2 } 

v = 33.1 m/s

v = u + at 

(v - u) / a = t 

[ (33.1 m/s) - (0.0 m/s) ] / (9.8 m/s^2) = 3.38 seconds

If the pigeon is 56.0 m below the initial position of the falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.