Answer:
Explanation:
Hello,
In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:
By knowing the volume and the concentration of the NaOH, one obtains:
Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:
Best regards.
This is not chemistry but
see it is a triangular prim on it's side
V=BH
are of base times height
the base is a triangle
height is 18.5
base=1/2bh
b=8.6
h=8.4
base=1/2(8.6)(8.4)
base=36.12
V=bh
V=36.12*18.5
V=668.22
round
V=668.2 ft^3
Solution :
A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.
We know,
In a standard cell,
the reduction half cell reaction is :
The oxidation half ell reaction :
Thus the complete reaction of the cell is :
cell = 
Molecular weight of N2
gram Atomic weight of N is 14 g.
gram Molecular weight = 14 g×2
= 28 g
Liter concepts
1 liter of gas always occupies 1 gram molecular weight .
Application of the concept
5.75 liter gives 0.257g
1 mole will occupy 28 g
0.257 will occupy 28 g × 0.257
= 7.196 g
The mass of the gas is 7.196 g.
Hope it helps you
