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Naddik [55]
3 years ago
10

List at least two chemical reactions that resulted in a white precipitate. For these reactions, list the possible chemical name

of the precipitate. What do these reactions (and the others with white precipitates) have in common?
If y'all could help, that'd be gr8
Chemistry
1 answer:
earnstyle [38]3 years ago
5 0
Try looking through this, don't actually read it if you don't want to but if you skim through it you might find answers. Good Luck! :) ..Reactions of Aldehydes, Ketones And Phenols Objective: 1. To carry out some simple chemicals test in order to distinguish between aldehydes, ketones and phenols 2. To study the properties of aldehydes, ketones and phenols. 3. To identify the unknowns A, B, C, D and E. Introduction: Part I : Reaction of Aldehydes and Ketones The carbonyl group is C=O and any compound containing this group that can be described as a carbonyl compound. Carbonyl compounds fall into two main classes: aldehydes and ketones on the one hand and carboxylic acids and their derivatives on the other hand. The characteristic reactions of the aldehydes and ketones are addition and oxidation reactions occurring at the unsaturated carbonyl group. With the same reagent, aldehydes usually react faster than ketones, mainly because there is lees crowding at the carbonyl carbon and the steric effect. Aldehydes are also more easily oxidized than ketones. The carbonyl and other compounds investigated in this experiment are tested in each of the following ways: A) Chromic Acid (H2CrO4) Chromic acid is a strong oxidant. Aldehydes are oxidized to carboxylic acids by chromic acid. The Cr6+ in the chromic acid which is orange, then is reduced to Cr3+ which is green/blue. Ketones are not oxidized by chromic acid.image B) Tollen’s Test (Ag(NH3)2+ / OH- Tollen’s reagent (Ag(NH3)2+ / OH- is a weak oxidant. Aldehydes are readily oxidized to carboxylic acids by Tollen’s reagent to produce a silver mirror on the inside of a clean test tube. Ketones are not oxidized by Tollen’s reagent.image C) Fehling’s solution Fehling’s solution is an oxidizing agent. It is prepared by mixing equal part of Fehling’s solution I (copper(II) sulfate) and Fehling’s solution II (sodium potassium tartate and sodium hydroxide). Aldehydes are easily oxidized to carboxylic acid by Fehling’s solution and will reduce the cupric ion which complexed with tartate ion to cuprous oxide. A positive result is indicated by the formation of a brick red precipitate. Ketones are not oxidized by Fehling’s solution.image D) 2,4-dinitrophenylhydrazine (DNP Test or Brady’s Reagent) 2,4-dinitrophenylhydrazine (Brady’s reagent) is an important reagent related to hydrazine. Most aldehydes and ketones very readily with this reagent to give the yellow orange and red precipitates of 2,4-dinitrophenylhydrazones. Unconjugated aldehydes and ketones give precipitates toward the yellow while conjugated compound tend to be deeper colour of red. The conversion of aldehydes and ketones into hydrazone is an example of the addition-elimination reaction occurring at the unsaturated carbonyl group.image E) Iodoform Test Iodoform test can be used for the detection of acetalaldehyde and all methyl ketone which have the formula:image Iodoform, CHI3 is a yellow solid with a strong medicinal smell. Iodoform will precipitate out of a mixture of methyl ketone, iodine and base.image For acetaldehyde, the following reaction shows the formation of iodoform:image Compounds that are easily oxidized to acetaldehyde and methyl ketones also give a positive iodoform test. Only ethanol can be oxidized to acetaldehyde and secondary alcohol that have the general formula CH3CH(OH)R can be oxidized to methyl ketones. Part II: Reactions
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A throat spray is 1.40% by mass Phenol, C6H5OH in water. If the solution has a density of 0.9956 g/ml, calculate the molarity of
myrzilka [38]

<u>Answer:</u> The molarity of solution is 1.08 M

<u>Explanation:</u>

We are given:

(m/m) of phenol = 1.40 %

This means that 1.40 g of phenol is present in 100 g of solution.

To calculate volume of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 0.9956 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

0.9956g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=100.442mL

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (phenol) = 1.40 g

Molar mass of phenol = 94.11 g/mol

Volume of solution = 100.442 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{1.40g\times 1000}{94.11g/mol\times 100.442mL}\\\\\text{Molarity of solution}=0.15M

Hence, the molarity of solution is 0.15 M

8 0
3 years ago
Consider an ionic compound, MX2, composed of generic metal M and generic, gaseous halogen X.
siniylev [52]

Lattice energy U(MX2) to calculate

Use Born-Haber(-Fajans) Cycle

http://en.wikipedia.org/wiki/Born%E2%80%...

M(s) + X2 → MX2(s) ΔHf°MX2 = -957 kJ mol^-1

M(s) →ΔHsub(M)→ M(g) ΔHsub = 123kJ mol^-1

M(g) →ΔHIE1(M)→ M^+ + e⁻ 757 kJ mol^-1

M^+→ΔHIE2(M)→ M^2+ + e⁻ 1451 kJ mol^-1

X2 →ΔHBE(X2)→ 2X +153 kJ mol^-1

X + e⁻→ΔHEA(X)→ X^- -313 kJ mol^-1

ΔHfo = U + ΔHsub(M) + IE1 + IE2 + ΔHdissX2 + 2EA1(X)

-957= U + 123 + 757 + 1451 + 153 – 626 = U + 1858

U = -2815 kJ mol^-1 The –ve sign is often dropped

5 0
4 years ago
A scientist named J. J. Thomson developed a model of the atom in which electrons are spread throughout a cloud of positive charg
vagabundo [1.1K]

Answer:

A small mass of positive charge was discovered in the center of the atom.

Explanation:

Atoms is the combination of protons, neutrons, as well as electrons particles. The particles that are in the centre of atom is Protons and neutrons, which made up the nucleus, this nucleus is surrounded by electron.

The discovery that directly caused scientists to revise this model of the atom is that A small mass of positive charge known as proton, and a positive charge particle was discovered by Ernest Rutherford, in the center of the atom in the year 1900. Ernest Rutherford through his research resulted to splitting of the atom during nuclear reaction and proton was discovered.

3 0
3 years ago
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