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lyudmila [28]
4 years ago
5

A fixed amount of gas occupies a volume of 7.25 l at a pressure of 4.52 atm. what will be the volume occupied if the pressure is

decreased to 1.21 atm at constant temperature?
Chemistry
1 answer:
Eddi Din [679]4 years ago
6 0
P1V1=P2V2
SO
7.25X4.52=1.21XV2
V2=27.1 l
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Answer:

I think it's a old river

Explanation:

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Answer:

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Explanation:

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6 0
3 years ago
A sample of gas has a mass of 827 mg . Its volume is 0.270 L at a temperature of 88 ∘ C and a pressure of 975 mmHg . Find its mo
avanturin [10]

Steps:

Mw = w * R * T / p * V

T = 88 + 273 => 361 K

p = 975 mmHg in atm :

1 atm  = 760 mmHg

975 mmg / 760 mmHg =>  1.28 atm

Therefore:

= 0.827 * 0.0821 * 361 /  1.28 * 0.270

=  24.51 / 0.3456

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7 0
3 years ago
Calculate the mass in grams of carbon needed to produce 160 g of CO2 in burning: C + O2 --&gt; CO2
Vladimir [108]
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
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5 0
3 years ago
Be sure to answer all parts.
Natali5045456 [20]

Answer:

38.7%

41.3%

20%

Explanation:

The percentage composition helps to know the what percent of the total mass of a compound is made up of each of the constituent elements or groups.

To solve this problem:

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  • place the mass contribution of the element or group to the formula mas and multiply by 100;

Compound:

 Ca₃(PO₄)₂

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%C = \frac{3(40)}{310} x 100  = 38.7%

%P = \frac{8(16)}{310} x 100  = 41.3%

%O = \frac{2(31)}{310} x 200  = 20%

8 0
3 years ago
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