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lyudmila [28]
3 years ago
5

A fixed amount of gas occupies a volume of 7.25 l at a pressure of 4.52 atm. what will be the volume occupied if the pressure is

decreased to 1.21 atm at constant temperature?
Chemistry
1 answer:
Eddi Din [679]3 years ago
6 0
P1V1=P2V2
SO
7.25X4.52=1.21XV2
V2=27.1 l
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Adding a catalyst to a system at equilibrium lowers the activation energy required by a system, which system, which shifts the e
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Answer: False

Explanation: Took the test

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What do the elements in each pair have in common? k, kr be, mg ni, tc b, ge al, pb?
tensa zangetsu [6.8K]
The pairs are:
K, Kr - Same period
Be, Mg - Same group
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4 0
3 years ago
Which description is true of 0.02 M Ca(OH)2 if Ca(OH)2 completely dissociates in water? A. It’s a dilute strong acid. B. It’s a
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Answer: B. It’s a dilute strong base.


Explanation:


1) Definition of acids and bases: as per Bronsted-Lowry model, an acid is a substance that donates hydrogen ions and a base is a substance that accepts hydrogen ions.

Ca(OH)₂ does not have hydrogen ions to donate, but it can accept hydrogen ions to form H₂O according to this equation: H⁺ + OH⁻ → H₂O.

Hence,  Ca(OH)₂ is a base.


2) Definition of strong base: a strong base is a base that dissociates completely into metallic and hydroxide ions in aqueous solutions, while a weak base dissociates partially.


Hence, Ca(OH)₂ is a strong base.


3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.


Therefore, we have found that the description of 0.02 M Ca(OH)₂ is that is is a dilute strong base (option B).


5 0
3 years ago
A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper
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Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

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             = \frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}

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As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

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When methane is completely combusted in oxygen forming carbon dioxide and
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Answer:

The masses of the reactants and products are equal.

Explanation:

Hope this helps.

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