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Goryan [66]
4 years ago
11

Active transport requires chemical energy. True False

Chemistry
2 answers:
guajiro [1.7K]4 years ago
6 0

Answer:

The answer is true

Explanation:

This process is called passive transport or facilitated diffusion, and does not require energy. The solute can move "uphill," from regions of lower to higher concentration. This process is called active transport, and requires some form of chemical energy.

shusha [124]4 years ago
6 0

Answer:

True

Explanation:

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What is the amount, in moles, of each elemental sample? a. 11.8 g Ar b. 3.55 g Zn c. 26.1 g Ta d. 0.211 g Li
spayn [35]

Answer:

A. 0.295 mole

B. 0.055 mole

C.0.144 mole

D. 0.03 mole

Explanation:

To find the amount in moles, we simply use a mathematical relation that connects mass, atomic mass and number of moles.

Number of moles = mass/atomic mass

A. Atomic mass of Argon is 40

n = 11.8/40 = 0.295 mole

B. Atomic mass of zinc is 65

n = 3.55/65 = 0.055 mole

C. Atomic mass of Tantalum is 181

n = 26.1/181 = 0.144 mole

D. Atomic mass of lithium is 7

n = 0.211/7 = 0.03 mole

8 0
3 years ago
which of these energy resources can produce the most amount of energy from the smallest amount of fuel? choices coal, uranium, p
nikitadnepr [17]
<span>The answer should be Uranium. As tiny amounts of that (rods normally) can fuel a whole nuclear energy station for years.</span>
6 0
3 years ago
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Which mass of urea CO(NH2)2 contain the same mass of nitrogen as 101.1g of potassium nitrate?
Sliva [168]
M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol

m(N)=M(N)m(KNO₃)/M(KNO₃)

m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)

2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)

m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))

m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g
7 0
3 years ago
A gas has experienced a small increase in volume but has maintained the same pressure and number of moles. According to the idea
valentinak56 [21]

Answer:

B it has increased slightly

Explanation:I took the test

4 0
3 years ago
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FILL IN THE BLANKS
viktelen [127]
I took the test I think the guy above is correct I’m not to sure good luck thanks
8 0
2 years ago
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