The best answer to report is 2.900 g/ml (answer A)
explanation
The best answer to report must be in four significant figures. 2.900 g/ml is therefore the best answer to report since in is in four significant. zeros placed after other digits but behind a decimal point are significant figures.,theerfore 2.900 has four significant figures
Answer:
1. Ok, so you have a 1:1 ratio of FeCl2 to FeCl3, which is shown by the fact that if you react 2 moles of FeCl2 you get 2 moles of FeCl3. So therefore, if you react 4 moles of FeCl2, you'd form 4 moles of FeCl3.
2. You have a 1:2 ratio of Cl2 to FeCl2, for every 1 mole of Cl2, you need 2 moles of FeCl2, so therefore, for 7 moles of Cl2, you need 2x7moles = 14 moles
3. 1:1 ratio. So you start with 2.28moles.
4. 1:2 ratio of Cl2 to FeCl2, so therefore to get from FeCl2 to Cl2 you need to divide by 2. Therefore, you need 3.25moles / 2 = 1.625 moles
Explanation:
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Answer:
a, b, c Flask B
Explanation:
The root mean square velocity of a gas is given by
V = √ ( 3RT/M)
where m is the molar mass, T is the temperature of the gas and R is the gas constant.
Therefore we have that the the velocity of the gas molecules is inversely proportional to the square root of the molar mass . That is the heavier the molecules the slower they will move which makes sense and the lower its kinetic energy.
The greater the velocity the more collisions the gas will have against the walls of the container.
The molar mass of CO and N2 are 28 g/mol while H2 is 2 g/mol. Hence hydrogen the lightest will have a greater kinetic enrgy, the greatest root mean square velocity and the greatest number of collisions with the wall of the container.
Notice that the pressure given for each is of the gases is different being the greatest for CO but pressure does not have an effect on the kinetic enery of the molecules.
Answer:5
Explann:
I've actually not learnt it but i can solve other questions under Maths
Answer:
because not enough of the parent isotope remains to measure accurately. because not enough of the daughter product has formed to be detectable.
Explanation:
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