Answer:
The true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The sample mean is 
The population standard deviation is 
From the question we are told the confidence level is 92% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 92% confidence interval is mathematically represented as
=>
=>
So the true estimate of the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval
69.58. 19.8x3=59.64 and 19.88/2 is 9.94. 59.64+9.94=69.58
(2x^2 + 16x + 30) / (5x^2 + 13x -6)
Start by factoring the numerator and denominator.
Cancel any like factors.
2(x^2 + 8x + 15)
2(x + 5)(x + 3) / (5x -2)(x + 3
2(x + 5) / (5x - 2)
The third choice
<span>This would be your answer 43 + 3n ≥ 70, so n ≥ 9
I hape this help</span>
Answer:
3
Step-by-step explanation:
22-19=3
Hope I helped have a great day <3