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Makovka662 [10]
3 years ago
9

the table below shows the number of the net calories Sylvia burns swimming for various numbers of minutes. Based on Sylvia's met

abolism, she must burn 3500 net calories to lose 16 ounces of fat. If Sylvia swims 30 minutes a day, about how many days will it take her to lose at least 5 pounds?
Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer is Fortnite default dance in text form.

⠀⠀⠀⠀⣀⣤

⠀⠀⠀⠀⣿⠿⣶

⠀⠀⠀⠀⣿⣿⣀

⠀⠀⠀⣶⣶⣿⠿⠛⣶

⠤⣀⠛⣿⣿⣿⣿⣿⣿⣭⣿⣤

⠒⠀⠀⠀⠉⣿⣿⣿⣿⠀⠀⠉⣀

⠀⠤⣤⣤⣀⣿⣿⣿⣿⣀⠀⠀⣿

⠀⠀⠛⣿⣿⣿⣿⣿⣿⣿⣭⣶⠉

⠀⠀⠀⠤⣿⣿⣿⣿⣿⣿⣿

⠀⠀⠀⣭⣿⣿⣿⠀⣿⣿⣿

⠀⠀⠀⣉⣿⣿⠿⠀⠿⣿⣿

⠀⠀⠀⠀⣿⣿⠀⠀⠀⣿⣿⣤

⠀⠀⠀⣀⣿⣿⠀⠀⠀⣿⣿⣿

⠀⠀⠀⣿⣿⣿⠀⠀⠀⣿⣿⣿

⠀⠀⠀⣿⣿⠛⠀⠀⠀⠉⣿⣿

⠀⠀⠀⠉⣿⠀⠀⠀⠀⠀⠛⣿

⠀⠀⠀⠀⣿⠀⠀⠀⠀⠀⠀⣿⣿

⠀⠀⠀⠀⣛⠀⠀⠀⠀⠀⠀⠛⠿⠿⠿

⠀⠀⠀⠛⠛

⠀⠀⠀⣀⣶⣀

⠀⠀⠀⠒⣛⣭

⠀⠀⠀⣀⠿⣿⣶

⠀⣤⣿⠤⣭⣿⣿

⣤⣿⣿⣿⠛⣿⣿⠀⣀

⠀⣀⠤⣿⣿⣶⣤⣒⣛

⠉⠀⣀⣿⣿⣿⣿⣭⠉

⠀⠀⣭⣿⣿⠿⠿⣿

⠀⣶⣿⣿⠛⠀⣿⣿

⣤⣿⣿⠉⠤⣿⣿⠿

⣿⣿⠛⠀⠿⣿⣿

⣿⣿⣤⠀⣿⣿⠿

⠀⣿⣿⣶⠀⣿⣿⣶

⠀⠀⠛⣿⠀⠿⣿⣿

⠀⠀⠀⣉⣿⠀⣿⣿

⠀⠶⣶⠿⠛⠀⠉⣿

⠀⠀⠀⠀⠀⠀⣀⣿

⠀⠀⠀⠀⠀⣶⣿⠿

⠀⠀⠀⠀⠀⠀⠀⠀⣤⣿⣿⠶⠀⠀⣀⣀

⠀⠀⠀⠀⠀⠀⣀⣀⣤⣤⣶⣿⣿⣿⣿⣿⣿

⠀⠀⣀⣶⣤⣤⠿⠶⠿⠿⠿⣿⣿⣿⣉⣿⣿

⠿⣉⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠛⣤⣿⣿⣿⣀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⣿⣿⣿⣿⣶⣤

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣤⣿⣿⣿⣿⠿⣛⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⠛⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣶⣿⣿⠿⠀⣿⣿⣿⠛

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⠀⠀⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠿⠿⣿⠀⠀⣿⣶

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⠛⠀⠀⣿⣿⣶

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⣿⣿⠤

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣶⣿

⠀⠀⣀

⠀⠿⣿⣿⣀

⠀⠉⣿⣿⣀

⠀⠀⠛⣿⣭⣀⣀⣤

⠀⠀⣿⣿⣿⣿⣿⠛⠿⣶⣀

⠀⣿⣿⣿⣿⣿⣿⠀⠀⠀⣉⣶

⠀⠀⠉⣿⣿⣿⣿⣀⠀⠀⣿⠉

⠀⠀⠀⣿⣿⣿⣿⣿⣿⣿⣿

⠀⣀⣿⣿⣿⣿⣿⣿⣿⣿⠿

⠀⣿⣿⣿⠿⠉⣿⣿⣿⣿

⠀⣿⣿⠿⠀⠀⣿⣿⣿⣿

⣶⣿⣿⠀⠀⠀⠀⣿⣿⣿

⠛⣿⣿⣀⠀⠀⠀⣿⣿⣿⣿⣶⣀

⠀⣿⣿⠉⠀⠀⠀⠉⠉⠉⠛⠛⠿⣿⣶

⠀⠀⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣿

⠀⠀⣿⣿⠀⠀⠀⠀⠀⠀⠀⠀⠉⠉

⣀⣶⣿⠛

⠀⠀⠀⠀⠀⠀⠀⣀⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⣿⣿⣿⣤⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣤⣤⣿

⠀⠀⠀⠀⠀⠀⠉⣿⣿⣿⣶⣿⣿⣿⣶⣶⣤⣶⣶⠶⠛⠉⠉

⠀⠀⠀⠀⠀⠀⣤⣿⠿⣿⣿⣿⣿⣿⠀⠀⠉⠀⠀⠀⠀⠀⠀

⠛⣿⣤⣤⣀⣤⠿⠉⠀⠉⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠉⠉⠉⠉⠉⠀⠀⠀⠀⠉⣿⣿⣿⣀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣶⣿⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⠛⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣛⣿⣿⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣶⣿⣿⠛⠿⣿⣿⣿⣶⣤⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⠛⠉⠀⠀⠀⠛⠿⣿⣿⣶⣀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⣿⣀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠛⠿⣶⣤⠀⠀

⠀⠀⠀⠀⠀⠛⠿⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣿⣿⠿⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠛⠉⠉⠀

⠀⠀⠀⠀⠀⠀⣤⣶⣶

⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣀⣀

⠀⠀⠀⠀⠀⣀⣶⣿⣿⣿⣿⣿⣿

⣤⣶⣀⠿⠶⣿⣿⣿⠿⣿⣿⣿⣿

⠉⠿⣿⣿⠿⠛⠉⠀⣿⣿⣿⣿⣿

⠀⠀⠉⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣤⣤

⠀⠀⠀⠀⠀⠀⠀⣤⣶⣿⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⣀⣿⣿⣿⣿⣿⠿⣿⣿⣿⣿

⠀⠀⠀⠀⣀⣿⣿⣿⠿⠉⠀⠀⣿⣿⣿⣿

⠀⠀⠀⠀⣿⣿⠿⠉⠀⠀⠀⠀⠿⣿⣿⠛

⠀⠀⠀⠀⠛⣿⣿⣀⠀⠀⠀⠀⠀⣿⣿⣀

⠀⠀⠀⠀⠀⣿⣿⣿⠀⠀⠀⠀⠀⠿⣿⣿

⠀⠀⠀⠀⠀⠉⣿⣿⠀⠀⠀⠀⠀⠀⠉⣿

⠀⠀⠀⠀⠀⠀⠀⣿⠀⠀⠀⠀⠀⠀⣀⣿

⠀⠀⠀⠀⠀⠀⣀⣿⣿

⠀⠀⠀⠀⠤⣿⠿⠿⠿

⠀⠀⠀⠀⣀

⠀⠀⣶⣿⠿⠀⠀⠀⣀⠀⣤⣤

⠀⣶⣿⠀⠀⠀⠀⣿⣿⣿⠛⠛⠿⣤⣀

⣶⣿⣤⣤⣤⣤⣤⣿⣿⣿⣀⣤⣶⣭⣿⣶⣀

⠉⠉⠉⠛⠛⠿⣿⣿⣿⣿⣿⣿⣿⠛⠛⠿⠿

⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⠿

⠀⠀⠀⠀⠀⠀⠀⠿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⣭⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⣤⣿⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⠿

⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⠿

⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠉⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠉⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⣿⠛⠿⣿⣤

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣿⠀⠀⠀⣿⣿⣤

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⠀⠀⠀⣶⣿⠛⠉

⠀⠀⠀⠀⠀⠀⠀⠀⣤⣿⣿⠀⠀⠉

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣤⣶

⠀⠀⠀⠀⠀⣀⣀⠀⣶⣿⣿⠶

⣶⣿⠿⣿⣿⣿⣿⣿⣿⣿⣿⣤⣤

⠀⠉⠶⣶⣀⣿⣿⣿⣿⣿⣿⣿⠿⣿⣤⣀

⠀⠀⠀⣿⣿⠿⠉⣿⣿⣿⣿⣭⠀⠶⠿⠿

⠀⠀⠛⠛⠿⠀⠀⣿⣿⣿⣉⠿⣿⠶

⠀⠀⠀⠀⠀⣤⣶⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⣿⣿⠒

⠀⠀⠀⠀⣀⣿⣿⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⣿⣿⣿⠛⣭⣭⠉

⠀⠀⠀⠀⠀⣿⣿⣭⣤⣿⠛

⠀⠀⠀⠀⠀⠛⠿⣿⣿⣿⣭

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠉⠛⠿⣶⣤

⠀⠀⠀⠀⠀⠀⣀⣿⠀⠀⣶⣶⠿⠿⠿

⠀⠀⠀⠀⠀⠀⣿⠛

⠀⠀⠀⠀⠀⠀⣭⣶

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣤⣤

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿

⠀⠀⣶⠀⠀⣀⣤⣶⣤⣉⣿⣿⣤⣀

⠤⣤⣿⣤⣿⠿⠿⣿⣿⣿⣿⣿⣿⣿⣿⣀

⠀⠛⠿⠀⠀⠀⠀⠉⣿⣿⣿⣿⣿⠉⠛⠿⣿⣤

⠀⠀⠀⠀⠀⠀⠀⠀⠿⣿⣿⣿⠛⠀⠀⠀⣶⠿

⠀⠀⠀⠀⠀⠀⠀⠀⣀⣿⣿⣿⣿⣤⠀⣿⠿

⠀⠀⠀⠀⠀⠀⠀⣶⣿⣿⣿⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠿⣿⣿⣿⣿⣿⠿⠉⠉

⠀⠀⠀⠀⠀⠀⠀⠉⣿⣿⣿⣿⠿

⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⠉

⠀⠀⠀⠀⠀⠀⠀⠀⣛⣿⣭⣶⣀

⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⠉⠛⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⣿⣿

⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣉⠀⣶⠿

⠀⠀⠀⠀⠀⠀⠀⠀⣶⣿⠿

⠀⠀⠀⠀⠀⠀⠀⠛⠿⠛⠀⠀⠀

⠀⠀⠀⣶⣿⣶

⠀⠀⠀⣿⣿⣿⣀

⠀⣀⣿⣿⣿⣿⣿⣿

⣶⣿⠛⣭⣿⣿⣿⣿

⠛⠛⠛⣿⣿⣿⣿⠿

⠀⠀⠀⠀⣿⣿⣿

⠀⠀⣀⣭⣿⣿⣿⣿⣀

⠀⠤⣿⣿⣿⣿⣿⣿⠉

⠀⣿⣿⣿⣿⣿⣿⠉

⣿⣿⣿⣿⣿⣿

⣿⣿⣶⣿⣿

⠉⠛⣿⣿⣶⣤

⠀⠀⠉⠿⣿⣿⣤

⠀⠀⣀⣤⣿⣿⣿

⠀⠒⠿⠛⠉⠿⣿

⠀⠀⠀⠀⠀⣀⣿⣿

⠀⠀⠀⠀⣶⠿⠿⠛

⠀

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What were the lengths of the legs of a right triangle in which measures 19 degrees and the hypotenuses 15 units long
Otrada [13]

Answer:



The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.

                     leg 1 = (15 units) x (cos 19) = 14.18 units

                     leg 2 = (15 units) x (sin 19) = 4.88 units

The lengths of the legs are 14.18 units and 4.88 units.  

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What point is plotted on the graph?<br><br> (9, 8)<br> (9, 9)<br> (8, 8)<br> (8, 9)
zhannawk [14.2K]

Answer:

It'd help to show the graph but, count out how far it goes right, than count up how far it goes up, the first number is x, the second number is y

Step-by-step explanation:

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AlekseyPX

Answer:

D. 220.16 Square feet

Step-by-step explanation: The shaded area is the space in the square not filled by the circle. So we need to find the area of the circle. The formula for area of a circle is A=\pi r^{2}. So we fill in this equation with the information we already know:

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Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

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<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
2 years ago
Jean runs 8 mi and then rides 11 mi on her bicycle on a biathlon. She rides 9 mph faster than she runs. If the total time for he
Ipatiy [6.2K]

Let Jean's speed while running = x mph

Then Jean's speed while riding will be = x+9 mph

Distance covered by running = 8 miles

Distance covered by riding = 11 miles

Total time taken to complete the race = 1.5 hours

As, time=\frac{distance}{speed}

So, time for running= \frac{8}{x}

And time for riding= \frac{11}{x+9}

Equation becomes:

\frac{8}{x}+\frac{11}{x+9}=1.5

Now, multiply every term by 2x(x+9) to clear denominators:  

16(x+9)+22x=3x(x+9)

Simplifying it we get

3x^{2}-11x-144=0

Solve the quadratic equation using formula

x= \frac{-b+\sqrt{b^{2}-4ac }}{2a}

putting a=3 , b= -11, c= -144

we get (x - 9)(3x + 16) = 0

where x=9 and x=\frac{-16}{3}

Neglect the negative answer as speed cannot be negative, so x = 9 mph

Hence, Jean's running speed is 9 mph and riding speed is x+9 = 9+9 = 18 mph

4 0
3 years ago
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