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velikii [3]
3 years ago
10

Density of a piece of wood that has a measurement of 24 cm3 and 768 g

Chemistry
2 answers:
Usimov [2.4K]3 years ago
5 0

Answer:

The density of wood is 32 g/cm³.

Explanation:

Given data:

Mass of wood = 768 g

Volume of wood = 24 cm³

Density of wood = ?

Solution:

Density is equal to the mass divided by its volume.

Formula:

d = m/v

d = density

m = mass

v = volume

d = 768 g/ 24 cm³

d = 32 g/cm³

<em>The density of wood is  32 g/cm³.</em>

Brut [27]3 years ago
4 0

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

We have the final answer as

<h3>32 g/cm³</h3>

Hope this helps you

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Find the mass in grams of aluminum nitrate, Al(NO3)3, required to mix with 750 g of water to makea 1.5m solution.
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Answer:
            Mass  =  239.62 g

Explanation:

Molality is given as,

                               m  =  Moles of Solute / Kg of Solvent   ---  (1)

Data Given;
                   Molality  =  1.5 m

                   Mass of Solvent  =  750 g  =  0.75 Kg

Solving eq. 1 for Moles,

                          Moles  =  Molality × Mass of Solvent

Putting values,
                          Moles  =  1.5 mol.Kg⁻¹ × 0.75 Kg

                          Moles  =  1.125 mol

Calculating mass from moles,

                          Moles  =  Mass / M.mass
Or,
                          Mass  =  Moles × M.mass

Putting values,
                          Mass  =  1.125 mol × 213 g.mol⁻¹

                          Mass  =  239.62 g
7 0
3 years ago
What is a limitation of using a chemical formula, such as C6H12O6, to represent a compound?
Yakvenalex [24]

Answer:

B

The chemical formula does not show how the atoms are connected to one another

7 0
3 years ago
Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat
Cloud [144]

Answer:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

Hg(l)+O_2\rightarrow HgO

Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

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8 0
3 years ago
Given the following reaction:
Semenov [28]

Answer:

The answer to your question is 0.35 moles of ZnCl₂

Explanation:

Data

moles of ZnCl₂ = ?

mass of Zn = 23 g

mass of CuCl₂ = excess

Balanced chemical reaction

             Zn + CuCl₂   ⇒   ZnCl₂  +  Cu

Process

1.- Convert the mass of Zn to moles

-Look for the atomic mass of Zn

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-Convert the grams to moles

            65.4 g -------------- 1 mol

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               x = (23 x 1)/65.4

               x = 23 / 65.4

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2.- Calculate the moles of ZnCl₂ using proportions and cross multiplication, and the coefficients of the balanced chemical reaction.

              1 mol of Zn ---------------- 1 mol of ZnCl₂

             0.35 moles of Zn --------  x

              x = (0.35 x 1) / 1

              x = 0.35 moles of ZnCl₂

7 0
3 years ago
What is the answer pllleeaasseeeee?????
kenny6666 [7]

I will try my best to sovle this question...

Im Pretty sure it has to be A. it needs to balance it would not stand in place if not balanced.

3 0
3 years ago
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