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4 years ago

If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature

Chemistry

1 answer:

Bezzdna [24]4 years ago

5 0

Answer:

The new volume of gas is 25.7 L.

Explanation:

Given data:

Initial volume = 24.0 L

Initial pressure = 10.0 atm

Initial temperature = 200 K

Final temperature = 300 K

Final volume = ?

Final pressure = 14.0 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 10.0 atm × 24.0 L × 300K / 200 K × 14.0 atm

V₂ = 72000 atm .L. K / 2800 K.atm

V₂ = 25.7 L

The new volume of gas is 25.7 L.

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12 = 3X X = <br> 7X = 57 X = <br> 11X = 27.7 X =

dybincka [34]

Answer:
1. $x=4$
2. $x=\frac{57}{7}$
3. $x=\frac{27.7}{11}$

Explanation:

Given the following questions:

$12=3x$
$7x=57$
$11x=27.7$

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
$12=3x$
$\frac{3x}{3} =\div3$
$12\div3=4$
$x=4$

Question two:
$7x=57$
$\frac{7x}{7} =\div7$
$57\div7=8.14285714=\frac{57}{7}$
$x=\frac{57}{7}$

Question three:
$11x=27.7$
$\frac{11x}{11} \div11$
$27.7\div11=2.51818182=\frac{27.7}{11}$
$x=\frac{27.7}{11}$

Hope this helps.

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