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Flauer [41]
3 years ago
9

Nitric acid reacts with silver metal 4hno3 + 3ag = no + 2h2o + 3agno3. calculate the number of grams of no formed when 10.8 g of

ag reacts with 12.6g of hno3
Chemistry
1 answer:
blagie [28]3 years ago
3 0
The balanced equation for the reaction is;
<span>2HNO</span>₃<span> + Ag ---> NO + 2H</span>₂O<span> + AgNO</span>₃
Stoichiometry of HNO₃ to Ag is 2:1
we need to first find the limiting reactant
number of HNO₃ moles - 12.6 g / 63 g/mol  = 0.2 mol
number of Ag moles - 10.8 g / 108 g/mol = 0.1 mol
0.2 moles of HNO₃ react with 0.1 mol of Ag, this is in the 2:1 molar ratio which means that both reactants react fully in the reaction.
then molar ratio of Ag to NO is 1:1
number of Ag moles equivalent to number of NO moles 
Number of NO moles - 0.1 mol
Mass of NO - 0.1 mol x 30 g/mol = 3 g
mass of NO produced is 3 g


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