Answer:
Eukarya
Explanation:
It's larger than a prokaryotic cell and it has a nucleus.
The combustion of Methane produces CO₂ and water;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to balance equation,
1 Mole of CH₄ on combustion give = 2 Moles of H₂O
So,
2 Moles of CH₄ will produce = X Moles of H₂O
Solving for X,
X = (2 Moles × 2 Moles) ÷ 1 Mole
X = 4 Moles
Result:
4 Moles of H₂O is produced on combustion of 2 Moles of CH₄.
Answer:
A. 6 water molecules, hydrogen is limiting.
Explanation:
For a molecule of water, you need 2 hydrogen atoms and 1 oxygen atom. Therefore, if there is 6 molecules of hydrogen and 6 molecules of oxygen, there are 12 atoms of hydrogen and 12 atoms of oxygen. You need 2 of hydrogen so you will divide 12 by 2. 12-2=6. You need only 1 atom of oxygen so it will stay as 12. The limiting reactant is hydrogen because there are only 6 while there are 6 atoms of oxygen remaining. There will only be 6 water molecules formed due to the insufficient amount of hydrogen.
Answer:
3,46 atm
Explanation:
Tenemos;
P1 =?
T1 = 100 + 273 = 373 K
V1 = 40 litros
P2 = 6 atmósferas
T2 = 50 + 273 = 323 K
V2 = 20 litros
Desde;
P1V1 / T1 = P2V2 / T2
P1V1T2 = P2V2T1
P1 = P2V2T1 / V1T2
P1 = 6 * 20 * 373/40 * 323
P1 = 44760/12920
P1 = 3,46 atm
They are notable d d d dndnf
