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EastWind [94]
3 years ago
13

ΔH for the formation of CuCl2 from its elements is -220.1 kJ/mol. How many kJ are associated with the formation of 0.30 mole of

CuCl2?
-66 kJ
-78 kJ
85 kJ
201 kJ
Chemistry
2 answers:
Mashcka [7]3 years ago
8 0

Answer:

\Delta _fH=-66.03kJ

Explanation:

Hello,

In this case, by knowing the enthalpy of formation of the copper (II) chloride is -220.1kJ/mol and there are 0.3 moles of such compound, the resulting whole energy is obtained by multiplying those values as the moles define the total energy as shown below:

\Delta _fH=-220.1\frac{kJ}{mol}*0.30mol\\ \Delta _fH=-66.03kJ

Best regards.

otez555 [7]3 years ago
3 0
0.3 * - 220.1 = - 66.03kJ
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alexira [117]
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                                          V₁T₂ = V₂T₁
Substituting the known values,
                                (0.456 L)(65 + 273.15) = (3.4 L)(T₁)
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5 0
3 years ago
Read 2 more answers
HC2H3O2 (aq) + H2O (l) ⇔ C2H3O2- (aq) + H3O+ (aq) Ka = 1.8 x 10-5
marin [14]

The concentration of [H3O⁺]=2.86 x 10⁻⁶ M

<h3>Further explanation</h3>

In general, the weak acid ionization reaction  

HA (aq) ---> H⁺ (aq) + A⁻ (aq)  

Ka's value  

\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

Reaction

HC₂H₃O₂ (aq) + H₂O (l) ⇔  (aq) + H₃O⁺ (aq) Ka = 1.8 x 10⁻⁵

\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}

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5 0
3 years ago
Help plzzzzz ASAP!!!!!!!!
SIZIF [17.4K]

1. NaF, Na₂S, Na₃P, Na₂O

2. MgF₂, MgS, Mg₃P₂, MgO

3. AlF₃, Al₂S₃, AlP, Al₂O₃

<h3>Further explanation</h3>

Given

Ionic charge

Required

The formula of binary ionic compounds

Solution

Ionic compounds consisting of cations (ions +) and anions (ions -)

Ionic compounds usually consist of metal cations and non-metal anions

Metal: cation, positively charged.

Nonmetal: negatively charged

The anion cation's charge is crossed

The ionic compounds :

1. NaF, Na₂S, Na₃P, Na₂O

2. MgF₂, MgS, Mg₃P₂, MgO

3. AlF₃, Al₂S₃, AlP, Al₂O₃

4 0
3 years ago
9. How many protons, neutrons, and electrons does 35C1l- have?
Alekssandra [29.7K]
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7 0
3 years ago
(03.05 LC)
Ainat [17]

Answer:

The correct answer is 4

Explanation:

Boron trifluoride (BF₃) has a molecular geometry (as shown in the image in the question) referred to as trigonal planar; this is because each of the the fluorine atoms/molecules (bonded to the central boron atom) is placed in such a way that they form the three "end points"/"domains" of an equilateral triangle. Hence, the correct option is the last option.

7 0
3 years ago
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