I got b 5)A sample of pure sodium-24 has an initial mass of 10.0 grams. How many grams of sodium-24 will remain at the end of 4 half-lives?
A. 0.315
B. 0.630
C. 5.00
D. 6.00
Answer:
P₂ = 5000 KPa
Explanation:
Given data:
Initial volume = 2.00 L
Initial pressure = 50.0 KPa
Final volume = 20.0 mL (20/1000=0.02 L)
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
50.0 KPa × 2.00L = P₂ × 0.02 L
P₂ = 100 KPa. L/0.02 L
P₂ = 5000 KPa
Because the older cells will not be able to function properly without the new cells taking over them. :)
Answer: energy needed to remove an electron from an atom or ion in the gas phase. Explanation: That is the very definition of ionization energy: ionization energy is the energy needed to remove (get appart) an electron from a neutral atom or ion in gas phase.Jun 19, 2016
We need to first add both of the solution volumes together 35+115=150. Now we can divide the volume of the ethanol by the total volume 35/150=.233. To double check we can multiply the total volume by the percentage of ethanol by volume we got as a solution 150x.233=35. So the percentage by volume of ethanol in the solution is .233x100=23.3%.