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Tems11 [23]
3 years ago
11

All the examples stated belos is an example of electric forces except _________. A)a neutron pushing on another neutron B)an ele

ctron pushing on a proton B)an electron pushing on another electron
Chemistry
2 answers:
dlinn [17]3 years ago
6 0
Among all the choices letter A is not an example of electric forces which is a neutron pushing on another neutron. Neutron do not have charge and a mass slightly larger than the proton. I hope my answer helps you. 
Mandarinka [93]3 years ago
4 0
All of the following are examples of electric force except A. A Neuton pushing on another Neutron. Neutrons are subatomic particles that possess no electrical charge.
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Why do copper ions go to the negative electrode
Snowcat [4.5K]
Its because the copper ions have a positive charge, therefore, they are attracted to a negative electrode.
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3 years ago
Common uses for halogen compounds
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Fluorine is used to strengthen the enamel of your teeth, it can be used in acid form to etch glass, and chlorine is used in our drinking water and swimming pools. They're all part of the halogen family
4 0
3 years ago
QUESTION 3
Bond [772]

Answer:

D

Explanation:

8 0
3 years ago
Please help me! I don't understand this at all. All the info is in the picture. Thank you so much!!!
kykrilka [37]

Answer:

H₂S + Cl₂ —> S + 2HCl

Explanation:

? + Cl₂ —> S + 2HCl

To balance the equation above, we must recognise what atoms are present in the products.

The products contains S, H and Cl.

Thus, S, H and Cl must also be present in the reactants.

Considering the equation given above, we can see clearly that H and S is missing in the reactants.

H and S together as a compound is expressed as H₂S.

Now, we shall input H₂S into the equation to obtain the complete equation. This is illustrated below:

? + Cl₂ —> S + 2HCl

H₂S + Cl₂ —> S + 2HCl

Next, we shall verify to see if the equation is balanced.

There are 2 atoms of H on both sides of the equation.

There are 2 atoms of Cl on both sides of the equation.

1 atom of S exist on both sides of the equation.

Thus, the equation is balanced.

3 0
3 years ago
In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolu
jekas [21]

Answer:

Explanation:

mass of the solution m = 1.6 + 75 = 76.6 g

fall in temperature = 25 - 23.34 = 1.66°C

heat absorbed = mass x specific heat x fall in temperature

= 76.6 x 1.66 x 4.18

= 531.5 J .

= .5315 kJ .

mol weight of ammonium nitrate = 80 g

heat absorbed by 1.6 g = .5315 kJ

heat absorbed by 80 g or one mole = 26.575 kJ

enthalpy change ΔH = +26.575 kJ

b )

enthalpy of hydration = 2630 kJ / mol

lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

= 2656.575 kJ  .

7 0
3 years ago
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