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mars1129 [50]
3 years ago
6

How many molecules are there in 39 grams of water

Chemistry
2 answers:
choli [55]3 years ago
8 0

Answer:

39 g H2O contains 1.3 ×1024molecules H2O.

Explanation:

yaroslaw [1]3 years ago
6 0

Answer:

I think its 117

Explanation:

H20

2*39 (hydrogens)

78

78+39(oxygens)

117

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If 14.3 moles of H2O2 is decomposed, how many grams of oxygen gas are produced?
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The balanced chemical reaction would be as follows:

2H2O2 = 2H2O + O2

We are given the amount of the peroxide that decomposes. Using this as the starting point for the calculations, we can determine the amount of O2 produced. We do as follows:

14.3 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 7.15 mol O2 produced
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1.* Write the name and symbol of the ion formed when
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1c) anion and N-3
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She needs to know the distance from LA to SF.

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Give two possible sets of four quantum numbers for the electron in hydrogen when it is in its lowest energy state.
konstantin123 [22]

Answer:

Explanation:

The electron in the lowest energy state will be found in 1 s energy level.

set of 4 possible quantum numbers

Principal quantum no : n = 1 ,

Azimuthal quantum no l = 0

Magnetic quantum no m = 0

Spin quantum no  s = + 1/2

set of other quantum nos

Principal quantum no : n = 1 ,

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4 0
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Question 2 of 50
wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

  1. Write the balanced chemical equation for the given reaction.
  2. Convert the mass of calcium carbonate into moles.
  3. Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
  4. Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

mol \ CaO \ = 0.2498 \ mol

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

\boxed {mass \ CaO \ = 14 \ g}

Learn More

  1. Learn more about stoichiometry brainly.com/question/12979299
  2. Learn more about mole conversion brainly.com/question/12972204
  3. Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0
3 years ago
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