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Marrrta [24]
3 years ago
9

Precalculus question help

Mathematics
1 answer:
Fittoniya [83]3 years ago
3 0
4 + 12/13 = 64/13
4 + 19/20 = 99/20
4 + 26/27 = 134/27
4 + 33/34 = 169/34
4 + 40/41 = 204/41

top: 64, 99, 134, 169, 204 
bottom: 13, 20, 27, 34, 41 

top:
35(1) + 29 = 64
35(2) + 29 = 99
35(3) + 29 = 134
35(4) + 29 = 169
35(5) + 29 = 204

bottom:
7(1) + 6 = 13
7(2) + 6 = 20
7(3) + 6 = 27
7(4) + 6 = 34
7(5) + 6 = 41



answer is C.

35n + 29
------------
 7n + 6


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What is the center of the equation (x+12)^2 + (y-9)^2= 35
Reil [10]

Answer:

(-12,9)

Step-by-step explanation:

The equation of a circle is given by the equation (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center point on the graph.

Therefore, in the equation (x+12)^2 + (y-9)^2 = 35, the center point on the graph would be (-12,9).

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The points P and Q in the following figure define the line segment (PQ⎯⎯⎯⎯⎯) P Q . The steps involved in using a compass to cons
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You haven't provided the steps.

mathisfun.com/geometry/construct-linebisect.html

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-21

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!<br><br> Graph g(x) = 3x^2 - 12x - 3
Paul [167]

Answer: Vertex = (2, -15)  2nd point = (0, -3)

<u>Step-by-step explanation:</u>

g(x) = 3x² - 12x - 3

      = 3(x² - 4x - 1)

          a=1   b=-4  c=-1

Find the x-value of the vertex by using the formula for the axis of symmetry: x = \dfrac{-b}{2a}

x = \dfrac{-(-4)}{2(1)}

      = \dfrac{4}{2}

         = 2

Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3

g(2) = 3(2)² - 12(2) - 3

       = 12  - 24 - 3

       = -15

So, the vertex is (2, -15)  ←  PLOT THIS COORDINATE

Now, choose a different x-value.  Plug it into the equation and solve for y. <em>I chose x = 0</em>

g(0) = 3(0)² - 12(0) - 3

       = 0  - 0 - 3

       = -3

So, an additional point is (0, -3)  ←  PLOT THIS COORDINATE


5 0
2 years ago
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