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sdas [7]
3 years ago
15

Wavelength (nm)n2E (J) 404.7 435.8 546.1 579.0 Show your work (or send in a separate sheet with your work on it): Q1: A sodium v

apor lamp is similar to a mercury vapor lamp. Sodium displays a single visible emission line at 589.3 nm. Why is it better to use a mercury vapor lamp for calibration purposes
Chemistry
1 answer:
lora16 [44]3 years ago
7 0

Answer: Please see answer below

Explanation:

Mecury vapor lamp is better to use than Sodium vapor light, this is because  because

---The Filaments of the lamp in sodium  emit fast moving electrons, which causes valence electrons of the sodium atoms to excite to higher energy levels which when electrons after being excited, relax by emitting yellow light which concentrates on the the  monochromatic bright yellow part of the visible spectrum which is about  580-590 or about (589nm) which will fall incident on the calibrations making it difficult to see

While

In Mercury vapor lamp, The emitted  electrons from the filaments, after having been excited  by high voltage, hit the mercury atoms but the excited electrons of mercury atoms relax and emits an  ultraviolet  uv invisible lights falling on the mecury vapour lamp to produce white light  covering  a wide range of  (380-780 nm) which is visible that is why it is used for calibrations purposes in  lightening applications.

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2 years ago
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in the following reaction, how many grams of benzene (C6H6) will produce 42 grams of CO2? 2C6H6 + 15O2 → 12CO2 + 6H2O
Mrrafil [7]

Answer: -

12.41 g

Explanation: -

Mass of CO₂ = 42 g

Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol

Number of moles of CO₂ = \frac{42}{44 g/mol}

= 0.9545 mol

The balanced chemical equation for this process is

2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O

From the balanced chemical equation we see

12 mol of CO₂ is produced from 2 mol of C₆H₆

0.9545 mol of CO₂ is produced from \frac{2 mol C6H6 x 0.9545 mol  CO2}{12 mol CO2}

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Mass of C₆H₆ =Molar mass x Number of moles

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8 0
3 years ago
Determine the bonding type for boron trihydride given the electronegativity on the Pauling scale for boron is 2.0 and for hydrog
Anika [276]

Answer: The bond between boron and hydrogen in boron trihydride is covalent bond.

Explanation:

The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms. According to the pauling's electronegativity rule:

  • If \Delta \chi=0, then the bond is non-polar.
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We are given:

Electronegativity for boron = 2.0

Electronegativity for hydrogen = 2.1

\Delta \chi=\chi_{H}-\chi_{B}\\\\\Delta \chi=2.1-2.0=0.1

As, \Delta \chi is less than 1.7 and not equal to 0. Hence, the bond between boron and hydrogen is covalent bond.

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If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees
telo118 [61]

Answer:

25.7 kJ/mol

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heat of solution of NH₄NO₃ + heat from water = 0

q₁  +  q₂  =  0

n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

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ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

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