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irina1246 [14]
3 years ago
12

I NEED HELP IT GIVES UOU 15 POINTS

Chemistry
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

I think the answer is: one element and one compound

Explanation:

I'm really sorry if it's wrong.

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A 25.0 mL sample of 0.105 M HCl was titrated to the equivalence point with 31.5 mL of NaOH. What is the concentration of the NaO
Andrei [34K]

Answer:  The concentration of NaOH is 0.08 M.

Explanation:-

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCl solution = 0.105 M

V_1 = volume of HCl solution = 25 ml

M_2 = molarity of NaOH solution = ?

V_2 = volume of NaOH solution = 31.5 ml

n_1 = valency of HCl = 1

n_2 = valency of NaOH = 1

1\times 0.105M\times 25=1\times M_2\times 31.5

M_2=0.08M

Therefore, the concentration of NaOH is 0.08 M.

5 0
3 years ago
several kinds of bears are found on earth. most bears are brown or black, but one type of bear, the polar bear is white. What pr
LekaFEV [45]

Explanation:

they are white so they can camouflage, but actually the polar bears skin is black and it's hair is hollow

4 0
3 years ago
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What should you always do at the end of a lab
Murrr4er [49]

Answer:clean up the area

Explanation:

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3 years ago
What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?
FrozenT [24]

Answer:

3.74 M

Explanation:

We know that molarity is moles divided by liters. The first thing to do here is convert your 1500 mL of solution to L. There's 1,000 mL in 1 L, so you need to divide 1500 by 1000:

1500 ÷ 1000 = 1.50

Now you can plug your values into the equation for molarity:

5.60 mol ÷ 1.50 L = 3.74 M

7 0
3 years ago
I need help asap thank u
UNO [17]
It is b, i learned this last year hope this helps
4 0
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