1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mote1985 [20]
3 years ago
15

Which of the following correctly describes what happens to the kinetic energy of water when it changes from steam to a

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
7 0

hi <3

i would say the kinetic energy decreases (so option C), as liquid particles are more closely packed than in a gas

hope this helps <3

You might be interested in
Based on this chart, which of the following statements describes sources of
Vera_Pavlovna [14]

Answer:A is correct

Explanation:

4 0
3 years ago
Read 2 more answers
Plz help me out!!!!!
Lelu [443]

Answer:

i am not 100% sure but im pretty sure there is.

Explanation:

7 0
3 years ago
What is the unit of measurement for mass?
Licemer1 [7]
Grams. It is a smaller unit. 
4 0
3 years ago
Given 7.45 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
KengaRu [80]

The equation for the reaction is:

C₄H₈O₂ + C₂H₅OH = C₆H₁₂O₂ + H₂O

Now you see that the number of the moles of butanoic acid and etyl butyrate is equal in

the reaction. That means;

number of moles of C₄H₈O₂ = number of moles of C₆H₁₂O₂

mass of C₄H₈O₂/ Molar mass of C₄H₈O₂ = mass of C₆H₁₂O₂/ molar mass of C₆H₁₂O₂

mass of C₆H₁₂O₂ = molar mass of C₆H₁₂O₂ x mass of C₄H₈O₂/ Molar mass of C₄H₈O₂

Now, assuming <span>100% yield, the mass of ethyl butyrate produced is: </span>

<span>= 7.45/88.11 x 116.16</span>

<span>=9.82g</span>

<span>Thus, the theoretical yield of ethyl butyrate is 9.82g.</span>

3 0
3 years ago
explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

3 0
2 years ago
Other questions:
  • Select the statement about mixtures that is correct. Select one: a. Suspensions are homogeneous mixtures of two or more componen
    15·1 answer
  • Which statement describes J.J. Thomson’s plum-pudding model of the atom?
    7·1 answer
  • Convert each quantity to the indicated units. a. 3.01g to cg. b. 6200m to km
    12·1 answer
  • Gas molecules are constantly in motion.<br><br> True or False?
    9·1 answer
  • In a constant‑pressure calorimeter, 70.0 mL of 0.350 M Ba(OH)2 was added to 70.0 mL of 0.700 M HCl. The reaction caused the temp
    11·2 answers
  • HNO3 + KOH → ____ + _____
    13·1 answer
  • 1. Which population of organisms depends on eating another population of organisms for
    5·1 answer
  • Using the model of the periodic table, which two elements pictured have similar chemical properties?
    10·2 answers
  • A beaker contains a solution. A single solute crystal is added to the solution. Immediately, crystals form in the solution. Whic
    14·1 answer
  • The molar mass of carbon dioxide is 44.0 g/mol. How many moles of CO2 are present in a 58.4 gram sample of CO2
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!