Answer:
H₂SO₄ (aq) + H₂O (l) → HSO₄⁻ (aq) + H₃O⁺ (aq)
HSO₄⁻ (aq) + H₂O (l) ⇄ SO₄⁻²(aq) + H₃O⁺ (aq) Ka
Explanation:
The sulfuric acid is a dyprotic acid.
It is a considered a strong acid but only the first deprotonation is strong.
Second deprotonation is totally weak
That's why we have equilibrium when it release the second proton.
Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium
10000 gallons= 37.85 cubic feet
Answer:
(4) concentrated and supersaturated
Explanation:
At 50.°C, 90g of KNO3 lies above the solubility curve [on the Regents Reference Table G]. This indicates that the solution is supersaturated, meaning it contains more solute than will naturally dissolve, and was formed when a saturated solution cooled. Furthermore, the percent concentration of this solution is 90% KNO3 making this solution concentrated. This can be calculated using the formula for mass percent concentration.
Percent Mass = <u>Mass of Solute (g)</u> x 100
Mass of Solution (g)
Equations represents the law of conservation of mass is 2H₂O → 2H₂ + O₂
Law of conservation of mass stated that energy neither be created nor destroyed called as law of conservation of mass and as the same no of each atom present in the both side of the reaction this reaction represents the law of conservation of mass so in the equation 2H₂O → 2H₂ + O₂ the energy cannot be created nor destroyed water can form 2 mole of hydrogen and 1 mole of oxygen which form water
Know more about law of conservation of mass
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Answer:
(a) Pair 1: H₂S and HS⁻
Pair 2: NH₃ and NH₄⁺
(b) Pair 1: HSO₄⁻ and SO₄⁻
Pair 2: NH₃ and NH₄⁺
(c) Pair 1: HBr and Br⁻
Pair 2: CH₃O⁻ and CH₃OH
(d) Pair 1: HNO₃ and NO₃⁻
Pair 2: H₃O⁺
Explanation:
When an acid loses its proton (H⁺), a conjugate base is produced.
When a base accepts a proton (H⁺), it forms a conjugate acid.
(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.
NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺
(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.
The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.
(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.
CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.
(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.
H₂O gains a proton to form the conjugate acid H₃O⁺.
