How many grams of iron metal do you expect to be produced when 265 grams of an 84.5 percent by mass iron (II) nitrate solution r

Question

DerKrebs [107]

3 years ago

9

How many grams of iron metal do you expect to be produced when 265 grams of an 84.5 percent by mass iron (II) nitrate solution r

eact with excess aluminum metal? Show all of the work needed to solve this problem.

Chemistry

2 answers:

Akimi4 [234] · Answer 1 · 2022-02-15T06:09:52+03:00

Akimi4 [234]3 years ago

8 0

265g solution x (84.5g Fe(NO3)2 / 100g solution) x (1 mole Fe(NO3)2 / __g Fe(NO3)2) x (3 moles Fe(s) / 3 moles Fe(NO3)2) x (__g Fe / mole Fe) = __g Fe

<span>plug in molar mass of Fe(NO3)2 and Fe and calculate</span>

Korolek [52] · Answer 2 · 2022-02-15T08:09:21+03:00

Korolek [52]3 years ago

8 0

<span>1.245*55.85= 69.53 gm iron metal will be produced</span>