Answer:
r1 = 5*10^10 m , r2 = 6*10^12 m
v1 = 9*10^4 m/s
From conservation of energy
K1 +U1 = K2 +U2
0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2
0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2
M is mass of sun = 1.98*10^30 kg
G = 6.67*10^-11 N.m^2/kg^2
0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))
v2 = 5.35*10^4 m/s
Answer:
115, 80, 15m
Explanation
t1 = 14s
t2 = 18s
change in time = 4s (18-14)
r(final) = r(initial) + (average velocity) x (change in time)
multiply the average velocity with the change in time
= (4, 0, -3) x 4 = 16, 0, -12
now we'll add this value to the initial position of the car
(99, 80, 27)m + (16, 0, -12)m = (115, 80, 15)m
She knows the speed limit in the area, and also saw the speed you were going on the speedometer. The speed you were going was faster than the limit allowed, so that's how she knew you were going too fast.
The distance of the canoeist from the dock is equal to length of the canoe, L.
<h3>
Conservation of linear momentum</h3>
The principle of conservation of linear momentum states that the total momentum of an isolated system is always conserved.
v(m₁ + m₂) = m₁v₁ + m₂v₂
where;
v is the velocity of the canoeist and the canoe when they are together
- u₁ is the velocity of the canoe
- u₂ velocity of the canoeist
- m₁ mass of the canoe
- m₂ mass of the canoeist
<h3>Distance traveled by the canoeist</h3>
The distance traveled by the canoeist from the back of the canoe to the front of the canoe is equal to the length of the canoe.
Thus, the distance of the canoeist from the dock is equal to length of the canoe, L.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
the formulae is f = mg = vpg