Question

A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is initially 3.0 m/s and the dove’s velocity is 2.0 m/s in the same direction?

Answer 1

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, $m_1=4\ kg$

Mass of dove, $m_2=1\ kg$

Initial velocity of falcon, $u_1=3\ m/s$

Initial velocity of dove, $u_2=2\ m/s$

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

V is the velocity after impact

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$V=\dfrac{4\times 3+1\times 2}{(4+1)}$

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.