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Galina-37 [17]
3 years ago
12

A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini

tially 3.0 m/s and the dove’s velocity is 2.0 m/s in the same direction?
Physics
1 answer:
Grace [21]3 years ago
7 0

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, m_1=4\ kg

Mass of dove, m_2=1\ kg

Initial velocity of falcon, u_1=3\ m/s

Initial velocity of dove, u_2=2\ m/s

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V is the velocity after impact

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{4\times 3+1\times 2}{(4+1)}

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

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