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seraphim [82]
3 years ago
8

What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?

Physics
1 answer:
Elis [28]3 years ago
3 0

K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 =  6 v²

800 / 6  =  v²

=   133.4    =v²

√133.4  =   √v²

11.5   =  v²

I hope this answer is correct.

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Answer:

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A 20 cm-radius ball is uniformly charged to 71 nC.
artcher [175]

Answer:

Part a)

\rho = 2.12\mu C/m^3

Part b)

q_1 = 1.11 nC

q_2 = 8.88 nC

q_3 = 71 nC

Part c)

E_1 = 3996 N/C

E_2 = 7992 N/C

E_3 = 15975 N/C

Explanation:

Part a)

As we know that charge density is the ratio of total charge and total volume

So here the volume of the charge ball is given as

V = \frac{4}{3}\pi R^3

V = \frac{4}{3}\pi(0.20)^3

V = 0.0335 m^3

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\rho = \frac{71 nC}{0.0335} = 2.12\mu C/m^3

Part b)

Now the charge enclosed by the surface is given as

q = \rho V

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q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.05)^3

q = 1.11 nC

at radius of 10 cm

q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.10)^3

q = 8.88 nC

at radius of 20 cm

q = 71 nC

Part c)

As we know that electric field is given as

E = \frac{kq}{r^2}

so we have electric field at r = 5 cm

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E_2 = \frac{(9\times 10^9)(8.88 nC)}{0.10^2}

E_2 = 7992 N/C

electric field at r = 20 cm

E_3 = \frac{(9\times 10^9)(71 nC)}{0.20^2}

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3 years ago
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<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>

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Resultant Force = Forward force + Reserve force

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Answer:

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