How much does a oil tanker weigh?

Tritium and helium-3 have the same number of nucleons, but tritium has one proton and two neutrons whereas helium-3 has two prot

ryzh [129]

Answer:

Tritium is more stable.

This happens in part because the tritium nucleus has an extra neutron enhancing the nuclear forces.

Explanation:

The binding energy is the energy that holds nucleons together in the nucleus. It depends on the number of nucleons present in the nucleus. The greater the number of nucleons, the greater the binding energy.

Also, the more the number of neutrons in a nucleus, the greater the nuclear forces. Helium-3 has only one neutron while tritium has two neutrons. The extra neutron in tritium enhances the nuclear forces hence tritium has a greater binding energy than Helium-3

6 0

3 years ago

What is the maximum kinetic energy of ejected electrons when photons of wavelength 300 nm hit a metal that has a work function o

Sonja [21]

Explanation:

Given that,

Wavelength of the photon, $\lambda=300\ nm=3\times 10^{-7}\ m$

Work function of the metal, $\phi=1.13\ eV=1.81\times 10^{-19}\ J$

We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :

$hf=E_k+\phi$

$E_k=hf-\phi$

$E_k=h\dfrac{c}{\lambda}-\phi$

$E_k=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{3\times 10^{-7}}-1.81\times 10^{-19}$

$E_k=4.82\times 10^{-19}\ J$

$E_k=3.01\ eV$

or

$E_k=3\ eV$

So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.

3 0

3 years ago

Your teacher had not exercised since the beginning of distance learning. She decided to exercise by walking in the park. The par

Lesechka [4]

A) 6000 m

B) 0 m

C) 3.33 m/s

D) 0 m/s

Explanation:

a)

In physics, distance is a scalar quantity that represents the total length of the path covered by an object during its motion.

Being a scalar quantity, it has no direction, but only a magnitude (so, a number + its units).

The distance covered by a body can be calculated by adding together all the lengths of all the motion of the body.

In this problem, the teacher walks in the partk, starting at position A, then walking around the park 5 times and returning to the original position.

The park has a rectangular shape 200 m x 400 m, so the perimeter of the park is:

$p=200+400+200+400=1200 m$

The teacher covers the perimeter 5 times, so the total distance she covered is:

$d=5p=5\cdot 1200 =6000 m$

B)

Displacement, instead, is a vector quantity that connects the initial position to the final position of the motion of an object.

Being a vector, it has both a magnitude and a direction, where:

- The magnitude is equal to the length of the vector, so it corresponds to the shortest distance in a straight line between the initial and final position

- The direction goes from the initial position to the final position

In this problem:

- The teacher starts her motion at position A

- The teacher ends her motion at position A

So, the distance between the initial and final position is zero:

$d=x_A -x_A = 0$

And therefore, the displacement is zero.

C)

The average speed of an object is a scalar quantity telling us how fast an object is moving, regardless of its direction of motion.

Being a scalar quantity, it has only a magnitude, and no direction.

The average speed is given by the equation:

$v=\frac{d}{t}$

where

d is the distance covered by the object

t is the time elapsed

In this problem we have:

d = 6000 m is the distance covered by the teacher

t = 30 min = 1800 s is the time elapsed

Therefore, the average speed is:

$v=\frac{6000}{1800}=3.33 m/s$

D)

The average velocity of an object is a vector quantity telling us how fast an object is moving but also its direction of motion.

Being a vector, it has both a magnitude and a direction, where:

- The direction corresponds to the direction of the displacement

- The magnitude is given by the formula:

$v=\frac{d}{t}$

where

d is the displacement of the object

t is the time elapsed

In this problem:

d = 0 is the displacement of the teacher

t = 1800 s is the time elapsed

Therefore, the average velocity is zero:

$v=\frac{0}{1800}=0 m/s$

7 0

3 years ago

A spaceship is 1600 m long when it is at rest. When it is traveling at a certain constant speed its length is measured by extern

Firdavs [7]

Answer:

speed of the spaceship is 0.495251 c

Time T = 1.4982 hr

Explanation:

given data

length L1 = 1600 m

length L2 = 1390 m

to find out

speed of the spaceship and time

solution

we know here

L2 = L1 × $\sqrt{1 - V^{2} }$

so we find V by put L1 and L2

1390 = 1600 × $\sqrt{1 - V^{2} }$

V = 0.495251 c

speed of the spaceship is 0.495251 c

and

we know T1 = 1.95 hr

so we find T2

T1 = T2 $\sqrt{1 - v^{2} }$

put here V and T1 so we get T2

1.95 = T2 $\sqrt{1 - 0.495251^{2} }$

Time T = 1.4982 hr

3 0

4 years ago

Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.

galina1969 [7]

Given:

The force of attraction is F = 48.1 N

The separation between the charges is

$\begin{gathered} r=\text{ 60.9 cm} \\ =\text{ 60.9}\times10^{-2}\text{ m} \end{gathered}$

Also, the magnitude of charge q1 = q2 = q.

To find the magnitude of charge.

Explanation:

The magnitude of charge can be calculated by the formula

$\begin{gathered} F=\frac{k(2q)}{r^2} \\ q=\frac{Fr^2}{2k} \end{gathered}$

Here, k is the Coulomb's constant whose value is

$k\text{ = 9}\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the magnitude of charge will be

$\begin{gathered} q=\frac{48.1\times(60.9^\times10^{-2})^2}{2\times9\times10^{^9}} \\ =9.91\times10^{-10}\text{ C} \\ =9.91\times10^{-4}\text{ }\mu C \end{gathered}$

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.

6 0

2 years ago