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dexar [7]
2 years ago
13

Adding a catalyst to a system at equilibrium lowers the activation energy required by a system, which system, which shifts the e

quilibrium position toward the products.
True or false?
Chemistry
2 answers:
GarryVolchara [31]2 years ago
8 0

Answer: False

Explanation: Took the test

Len [333]2 years ago
5 0

False is the correct answer.

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In the reaction Mg(s) + 2H2O(l) --> Mg(OH)2(s) + H2(g), what is the oxidation state of each H in H2(g)? A. +2 and –2 B. –1 an
chubhunter [2.5K]
The oxidation state of the atoms of any molecule in the element state equals zero. H2 is is the element state, therefore the oxidation state of the whole molecule equals zero and the oxidation states of the atoms also equals zero. Answer letter D is the correct answer. 
Magnesium has an oxidation state = zero before it undergoes the reaction and is oxidized. The oxidations state of the magnesium in Mg(OH)2 is +2.
6 0
2 years ago
What is the product of radioactive decay He called?
Zinaida [17]

Answer:

Alpha, Beta, and Gamma particles according to ability to penetrate matter.

Explanation:

  • Alpha represent the largest particle which penetrates the least with a positive charge,
  • Beta particles carry a negative charge, and
  • Gamma rays are neutral.
3 0
2 years ago
How does the size change when an atom forms a cation and when an atom forms an anion?
mario62 [17]
<span>A cation is an atom that loses a valence electron. When a valence electron is released there is one electron less to create a repulsive force. The loss of a repulsive force will allow the atom to pull tighter together. An anion would therefore be larger in size due to increased repulsion of the valence electrons.</span>
8 0
3 years ago
How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?
Ksenya-84 [330]

Answer:

a. Approximately 1.3\; \rm mL.

b. Approximately 7.2\; \rm mL.

Explanation:

The unit of concentration "\rm M" is equivalent to "\rm mol \cdot L^{-1}", which means "moles per liter."

However, the volume of both solutions were given in mililiters \rm mL. Convert these volumes to liters:

\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L.

\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L.

In a solution of volume V where the concentration of a solute is c, there would be c \cdot V (moles of) formula units of this solute.

Calculate the number of moles of \rm NaCl formula units in each of the two solutions:

Solution in a.:

n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol.

Solution in b.:

n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol.

What volume of that 3.4\; \rm M (same as 3.4 \; \rm mol \cdot L^{-1}) \rm NaCl solution would contain that many

For the solution in a.:

\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL.

Similarly, for the solution in b.:

\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL.

8 0
2 years ago
What is the initial temperature of 50g of water that was raised to 50*C by the addition of 4.18kJ of heat energy? (2 sig fig)
Alekssandra [29.7K]

Answer:

50

Explanation:

7 0
2 years ago
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