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dexar [7]
2 years ago
13

Adding a catalyst to a system at equilibrium lowers the activation energy required by a system, which system, which shifts the e

quilibrium position toward the products.
True or false?
Chemistry
2 answers:
GarryVolchara [31]2 years ago
8 0

Answer: False

Explanation: Took the test

Len [333]2 years ago
5 0

False is the correct answer.

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How many grams of aluminum will be deposited by 0.1F? (Al=27) a.0.3g b. 0.9. c. 9.0g. d. 2.7g<br>​
andrezito [222]

Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.

<h3>What is electrolysis?</h3>

Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.

The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.

Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium

0.1 F will discharge = 0.1/3 × 27 g of aluminium

mass of aluminium deposited = 0.9 g of aluminium.

Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.

Learn more about electrolysis at: brainly.com/question/26050361

5 0
2 years ago
Determine the mole ratio between oxygen and water for the following equation:
vodka [1.7K]

Answer:2.2

Explanation:

5 0
2 years ago
A sample of neon gas occupies a volume of 752 mL at
MatroZZZ [7]

Answer:

815mL am 10000000% sure

7 0
2 years ago
Dioxane, C4H8O2, has an enthalpy of fusion of 145.8 J g–1 and its melting point temperature is 11.0 °C. How much heat is require
kumpel [21]

Answer:

20703.6J

Explanation:

Quantity of heat (Q) = mass of dioxane × enthalpy of fusion

Mass of dioxane = 142g

Enthalpy of fusion of dioxane = 145.8J/g

Q = 142g × 145.8J/g = 20703.6J

5 0
3 years ago
What is the age of mummified primate skin that contains 8.25% of the original quantity of 14C?
rjkz [21]

Answer:

20619.4793 years

Explanation:

The half life of carbon-14 = 5730 years

The formula for the half life for a first order kinetic reaction is:

t_{1/2}=\frac {ln\ 2}{k}

Where,  

t_{1/2} is the half life

k is the rate constant.

Thus rate constant is:

5730 years=ln(2)/k

k = 1.21×10⁻⁴ years ⁻¹

Using integrated rate law as:

ln\ \frac {A_t}{A_0}=-k\times t

Where,

A_t is the concentration at time t

A_0 is the initial concentration

Given that the final concentration contains 8.25 % of the original quantity which means that:

\frac {A_t}{A_0}=0.0825

So,

ln(.0825)= -1.21×10⁻⁴×t

<u> t = 20619.4793 years</u>

<u></u>

8 0
3 years ago
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