Hey there,
Friction is important to increase the friction between the bars and the gymnast to prevent the gymnast from falling and hurting themselves.

Hope this helps :))

~Top♥

8 0

3 years ago

How fast would the car need to go to double its kinetic energy?

boyakko [2]

Answer:

$v_{f} = \sqrt{2}\cdot v_{o}$

Explanation:

Let consider a car travelling at a speed $v_{o}$ . The ratio of final kinetic energy to initial kinetic energy:

$\frac{\frac{1}{2}\cdot m \cdot v^{2}_{f} }{\frac{1}{2}\cdot m \cdot v^{2}_{o}} = 2$

$\frac{v_{f}}{v_{o}} = \sqrt{2}$

The final speed is:

$v_{f} = \sqrt{2}\cdot v_{o}$

3 0

3 years ago

Read 2 more answers

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A pipe closed at both ends can have standing wav

uranmaximum [27]

Answer:

68.8 Hz

137.6 Hz, 206.4 Hz

Explanation:

L = Length of tube = 2.5 m

v = Velocity of sound in air = 344 m/s

Distance between nodes is given by

$L=\dfrac{\lambda}{2}+m\dfrac{\lambda}{2}\\\Rightarrow \dfrac{\lambda(n+1)}{2}=L\\\Rightarrow \lambda=\dfrac{2L}{n+1}$

Where n = 0, 1, 2, 3, ...

Making n+1 = n

$\lambda=\dfrac{2L}{n}$

where n = 1, 2, 3 .....

For fundamental frequency n = 1

$\lambda=\dfrac{2\times 2.5}{1}\\\Rightarrow \lambda=5\ m$

Frequency is given by

$f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{344}{5}\\\Rightarrow f=68.8\ Hz$

The fundamental frequency is 68.8 Hz

First overtone

$2f=2\times 68.8=137.6\ Hz$

Second overtone

$3f=3\times 68.8=206.4\ Hz$

The overtones are 137.6 Hz, 206.4 Hz

4 0

3 years ago

Why is area called scalar quantity

astraxan [27]

Answer:

Explanation:

Commonly area is a scalar quantity because there is no need of direction to define and also follow the algebrac summation. When we talk about vector there exist a frame of reference with a certain orogin

8 0

2 years ago