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Gala2k [10]
2 years ago
6

What are three types of variables in a controlled experiments?

Physics
1 answer:
blsea [12.9K]2 years ago
7 0

The answers to your question are,

Independent, Dependent, and Control.

-Mabel <3

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The answer is c nitrogen thx me later
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Heat likes to remain <br> ONMFRIU ← Whats that unscrambled?
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3 years ago
In 2007, michael carter (u.s.) set a world record in the shot put with a throw of 24.77 m. what was the initial speed of the sho
Serga [27]

The initial speed of the shot is 15.02 m/s.

The Shot put is released at a height y<em> </em>from the ground with a speed u. It is released at an angle θ to the horizontal. In a time t, the shot put travels a distance <em>R</em> horizontally.

Pl refer to the attached diagram.

Resolve the velocity u into horizontal and vertical components, u ₓ=ucosθ and uy=u sinθ. The horizontal component remains constant in the absence of air resistance, while the vertical component varies due to the action of the gravitational force.

Write an expression for R.

R=u_xt=(ucos \theta)t

Therefore,

t=\frac{R}{ucos\theta} .......(1)

In the time t, the net displacement of the shotput is y in the downward direction.

Use the equation of motion,

y=u_yt-\frac{1}{2}gt^2=(usin\theta) t-\frac{1}{2}gt^2

Substitute the value of t from equation (1).

y=(ucos\theta)(\frac{R}{ucos\theta} )-\frac{1}{2} g(\frac{R}{ucos\theta} )^2\\ =Rtan\theta-(\frac{gR^2}{2u^2cos^2\theta} )

Substitute -2.10 m for y, 24.77 m for R and 38.0° for θ and solve for u.

y=Rtan\theta-(\frac{gR^2}{2u^2cos^2\theta} )\\ (-2.10m)=(24.77 m)(tan38.0^o)-\frac{(9.8 m/s^2)(24.77m)^2}{2u^2(cos38.0^o)^2} \\ u^2=225.71(m/s)^2\\ u=15.02m/s

The shot put was thrown with a speed 15.02 m/s.




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2 years ago
You have a chart that illustrates a series of species with their common ancestor. This chart is a
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The answer is *C. Cladogram*.
8 0
3 years ago
a 40 kilogramstudent runs up a staircase to a floor that is 5.0 meters higher than her starting point in 7.0 seconds. the studen
Wittaler [7]

When she reaches the top, she has more potential energy than she had at the bottom.

         Potential energy = (mass) x (gravity) x (height)

                                     = (40 kg) x (9.8 m/s²) x (5 m)

                                     =    1,960 more joules .

         Power = (energy) / (time)

                     = (1,960 joules) / (7 seconds)

                     =         280 watts

                    (about 0.375 horsepower) 
3 0
2 years ago
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