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3 years ago

Which one is a decomposition reaction?

Chemistry

2 answers:

vodomira [7]3 years ago

8 0

Answer:

b no

Explanation:

because it is decomposing into two elements

Serga [27]3 years ago

6 0

The Answer is b :)))

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Which of the following best defines balanced forces?

Mars2501 [29]

Answer:

Balanced forces are forces that act in opposite directions and cancel each other out

let me know if you have any other questions

6 0

2 years ago

Read 2 more answers

(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What i

oee [108]

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where, $P_{1}$ and $P_{2}$ represent initial and final pressure respectively

$V_{1}$ and $V_{2}$ represent initial and final volume respectively

$T_{1}$ and $T_{2}$ represent initial and final temperature (in kelvin) respectively

Here, $T_{1}=T_{2}$ , $V_{1}=50.0mL$ , $P_{1}=20.0atm$ and $P_{2}=40.0atm$

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL$

So, the new volume is 25.0 mL

6 0

3 years ago

Henry finds an element that is light blue, breaks easily in his hand, and does not reflect light. How should Henry classify the

pshichka [43]

Answer:

The options are not given, here are the options.

metal

a. Metal

b. a metalloid

c. a non-metal

d. a gas

The correct option is C.

Non metal

Explanation:

Henry should classify it as non metals because non metals are substances or elements that are poor conductors of heat and electricity they break easily I .e meaning they lack the ducibility of metals, meaning they cannot be stretched, they are brittle, they are not shiny and does not reflect light, they have high electronegativities that is they have atoms that can hold electrons to what they have.

4 0

3 years ago

You are carrying out an experiment in the lab to study the glycolysis pathway. To do this, a liver extract (which is capable of

Virty [35]

Answer:

When C1 is labeled in glucose, it ends up in the methyl group of pyruvate.

Aldolase cleaves a hexose into two trioses.

[See the image attached].

Asterisk indicates the label.

When C1 is labeled in glucose, it ends up in the carboxyl group of pyruvate.