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notka56 [123]
3 years ago
8

A basket has a mass of 5.5 kg. Find the magnitude of the normal force if the basket is at rest on a ramp inclined above the hori

zontal at:
---
a) 0 degrees (horizontal surface)
b) 12 degrees
c) 25 degrees
d) 45 degrees


can you write the answer and the steps how you found the magnitude
Physics
2 answers:
storchak [24]3 years ago
8 0
Here is the correct answer of the given problem above.
Given that the basket has a mass of 5.5kg, the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal is at 12 degrees. The solution is simple: 
<span>Fn at rest = lmgl </span>
<span>= 5.5kg (9.80N/kg) 
=</span><span> mgCos12degrees 
Hope this answer helps. </span>
miskamm [114]3 years ago
4 0

Answer:

(a) 53.9 N

(b) 52.72 N

(c) 48.85 N

(d) 38.11 N

Explanation:

The normal force is always perpendicular to the surface.

(a) the normal force = m x g = 5.5 x 9.8 = 53.9 N

(b) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 12 = 52.72 N

(c) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 25 = 48.85 N

(d) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 45 = 38.11 N

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A meteor is the flash of light that we see in the night sky when a small chunk of interplanetary debris burns up as it passes through our atmosphere. "Meteor" refers to the flash of light caused by the debris, not the debris itself.

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3 years ago
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A car moves forward up a hill at 12 m/s with a uniform backward acceleration of 1.6 m/s2. What is its displacement after 6 s?
Romashka [77]

Answer:

The displacement of the car after 6s is 43.2 m

Explanation:

Given;

velocity of the car, v = 12 m/s

acceleration of the car, a = -1.6 m/s² (backward acceleration)

time of motion, t = 6 s

The displacement of the car after 6s is given by the following kinematic equation;

d = ut + ¹/₂at²

d = (12 x 6) + ¹/₂(-1.6)(6)²

d = 72 - 28.8

d = 43.2 m

Therefore, the displacement of the car after 6s is 43.2 m

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2 years ago
Find the electron and hole concentrations and fermi level in silicon at 300 k for boron
gogolik [260]

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x 10^4 cm^-3.

<h3>Calculation and Explanation</h3>

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at 10^{15} cm^{-3} (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = 10^{15} cm^{-3}

np = \frac{ni^2}{nA}

np = \frac{(9.65 x 10^9)^2}{10^15}

np= 9.3 x 10^4 cm^-3

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x 10^{19} / 10^{15} )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

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Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

To know more about ionization energy, visit:

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4 0
1 year ago
In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it, causing the victim to land
Marina CMI [18]

Answer:

(a) \vec{J}=176.4\frac{kg*m}{s} \hat{j}

(b) F=2125.30N

Explanation:

(a) According to the law of conservation of energy, the potential energy of the person at 0.40 m is equal to its kinetic energy before the colision with the floor:

\Delta U=\Delta K\\mgh=\frac{mv^2}{2}\\v=\sqrt{2gh}\\v=\sqrt{2(9.8\frac{m}{s^2})(0.40m)}\\v=2.8\frac{m}{s}

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(b) The average force is:

F=\frac{J}{\Delta t}\\F=\frac{176.4\frac{kg*m}{s}}{0.083s}\\F=2125.30N

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