If a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.
<u>Explanation:</u>
Relative permittivity of a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.
It is given by the expression
k=k=ε /ε0
where ε denotes absolute permittivity and ε0 denotes permittivity of vacuuum.
Absolute permittivity ε of vacuum= ε0
therefore k= ε0/ ε0=1
dielectric constant of vacuum is 1 .
Answer:
82.3 J
Explanation:
PE = mgh
PE = (2.80 kg) (9.8 m/s²) (3.00 m)
PE = 82.3 J
oof, that question is difficult! i would say its d because if you pull a slingshot farther than another one, it would have more potential energy.
When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation
here by energy conservation we can say that
change in kinetic energy of electron = electrostatic potential energy gained through given potential difference
kinetic energy is given as

electrostatic potential energy is given as

now by energy conservation

given that for electron



now by plug in values



So here it is accelerated through potential difference of 2559.4 Volts
The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.
The formula for calculating the volume of a cylinder is given below.
V = πr^2 h
Get the differential of the volume as shown:
dV = V/ h dh + V / r dr
V/ h = πr^2
V/ h = 2 πr h
Now, the differential becomes
dV = πr^2dh + 2πrh dr
Given the following parameters i.e. diameter and height
dh = 0.1 + 0.1 = 0.2 cm
dr = 0.05 cm
h = 10 cm
d = 4 cm
r = 2cm
Substituting the values in the above equation, we get
dV = 3.14(2)^2(0.2) + 2(3.14)(2)(10)(0.05)
dV = 2.512 + 6.28
dV = 8.792 cm
dV = 8.8 cm
If you need to learn more about diameter click here:
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