Question

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near its center. You have enough wire for 3800 circular turns, and the solenoid must be 1.60 m long and 20.0 cm in diameter. What current will you need to produce the necessary field?

Answer 1

Answer:

Explanation:

Magnetic field = permeability x turn density x current

Magnetic field = 0.22T

turn density = 4150 /1.6 = 2593.75 t/m

permeability : µ = k µ°

µ°= 4 π 10^-7

k = 1

I = 0.22 / 4 π 10^-7 * 2593.75 = 0.22 10^7 /32594 = 67.497 A