If the cross-section of a wire of fixed length is doubled, the resistance of that wire change into doubled.We know that <span>the total </span>length<span> of the wires will </span>affect<span> the amount of </span>resistance. <span> The longer the wire, the more </span>resistance<span> that there will be so the answer is doubled.</span>
The distance a dropped object falls, with gravity and no air resistance:
Distance = (1/2) (acceleration) (falling time)²
Without air resistance, the horizontal motion has no effect on the fall.
Acceleration of Earth gravity = 9.8 m/s²
Distance = (1/2) (acceleration) (falling time)²
Distance = (1/2) (9.81 m/s²) (3.0 s)²
Distance = (0.5) x (9.81 m/s²) x (9.0 s²)
Distance = (0.5 x 9.81 x 9.0) (m-s² / s²)
Distance = 44.15 meters
We don't care how fast the bird was flying horizontally. It doesn't change anything. (It DOES determine how far ahead of the drop point the clam hits the ground. Most problems like this ask for that distance. This one didn't.)
The final velocity before takeoff is 104.96 m / s.
<u>Explanation:</u>
The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.
To calculate the final velocity,
V = u + at
where v represents the final velocity,
u represents the initial velocity,
a represents the acceleration
t represents the time taken.

v = 104.96 m / s.
The Linear momentum depends on
1) Mass
2) Linear Velocity
The angular momentum depends on
1) Inertia
2) Rotational velocity
Answer:
The location of helicopter is behind the packet.
Explanation:
As the packet also have same horizontal velocity as same as the helicopter, and also it has some vertical velocity as it hits the ground.
The horizontal velocity remains same as there is no force in the horizontal direction. The vertical velocity goes on increasing as acceleration due to gravity acts.
So, the helicopter is behind the packet.