Iwill need to use more force to stopa<br> O Lighter mass<br> O Heavier mass

What is the mass of an atom that has 4 protons, 5 neutrons, and 4 electrons? Please explain. This is a final exam question. Plea

12345 [234]

Answer:

9

Explanation:

You get this answer by adding the protons and neutrons together.

5 0

3 years ago

Drug abuse is best defined as __________.

Paul [167]

Answer:

Drug abuse is best defined as the nonmedical or improper use of a drug that can interfere with a healthy life.

For example, a person that is addicted to cocaine will use it everyday, and will develope agressive behavior, anxiety, sleep disorder, paranoia etc.

This person could get addicted at the point of comiting a robbery, killing and much more.

5 0

3 years ago

g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the

MrRa [10]

Answer:

Approximately $-1.58\; \rm rad \cdot s^{-2}$ .

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

$v^2 - u^2 = 2\, a\, x$ ,

where

$v$ is the final velocity of the moving object,
$u$ is the initial velocity of the moving object,
$a$ is the (linear) acceleration of the moving object, and
$x$ is the (linear) displacement of the object while its velocity changed from $u$ to $v$ .

The angular analogue of that equation will be:

$(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ , where

$\omega(\text{final})$ and $\omega(\text{initial})$ are the initial and final angular velocity of the rotating object,
$\alpha$ is the angular acceleration of the moving object, and
$\theta$ is the angular displacement of the object while its angular velocity changed from $\omega(\text{initial})$ to $\omega(\text{final})$ .

For this object:

$\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}$ , whereas
$\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}$ .

The question is asking for an angular acceleration with the unit $\rm rad \cdot s^{-1}$ . However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

$\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}$ .

Rearrange the equation $(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ and solve for $\alpha$ :

$\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}$ .

7 0

3 years ago

Fill in the blank

nignag [31]

Answer:

temperature

Explanation:

when you put a water on the stove the water will start to boil there for temperature

5 0

3 years ago

HEY CAN ANYONE PLS ANSWER DIS!!!!!!!

Radda [10]

Answer:

A) the one with the lower boiling point.

Please mark me brainliest! Hope this helped!

God bless :)

7 0

3 years ago

Iwill need to use more force to stopa O Lighter mass O Heavier mass