Answer:
The runner's average acceleration is 0.102 m/s²
Explanation:
The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m
We need to find the runner's average acceleration
The given is:
→ Initial velocity 5 m/s
→ Final velocity 5.2 m/s
→ Distance 10 meters
→ Acceleration ?
We need a suitable rule for the given
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, a is the acceleration
and s is the distance
Substitute the values above in the rule
→ (5.2)² = (5)² + 2 a (10)
→ 27.04 = 25 + 20 a
Subtract 25 from both sides
→2.04 = 20 a
Divide both sides by 20
→ a = 0.102 m/s²
<em>The runner's average acceleration is 0.102 m/s²</em>
Answer:
Explanation:
The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated β, γ- unsaturated ketones, like 3-cyclohexanone to their conjugated α, I²- unsaturated isomers.
Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an α- hydrogen from the protonated 3-cyclo hexanone to yield ethanol
2-cyclo hexanone can be obtained by acid catalyzation of 3-cyclohexanone isomers through the formation of it's "enol".
As kinetic energy increases, substance temperature increases
Power = work/time = (Force times distance)/time
= (30N *10.0m)/5.00s = 300/5 = 60 Watts
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