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azamat
3 years ago
15

?cobalt has a density of 8.90 g. what volume would 17.8 g of Cobalt occupy?

Chemistry
1 answer:
Airida [17]3 years ago
5 0

Answer:

Explanation:

Given parameters:

Density of cobalt = 8.9gcm⁻³

Mass of cobalt = 17.8g

Solution

Density can be defined as the mass per unit volume of a substance:

                      Density = \frac{mass in g}{volume in cm^{3} }

The unknown in the problem is Volume:

                    Volume = \frac{mass}{Density}

                     Volume =   \frac{17.8}{8.9} = 2cm³

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Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

8 0
3 years ago
Is MgCO3 organic or inorganic
schepotkina [342]
Its inorganic as MgCO3 is contains no carbon more hydrogen which is a crutial component of all organic compounds 
4 0
3 years ago
Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
vichka [17]

Answer:

3.

Explanation:

Hello,

In this case, it is convenient to write the chemical reaction as:

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

Which balanced turns out:

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Thus the number that should be in front of the calcium sulfate is 3 in order to balance the reaction.

Best regards.

8 0
3 years ago
Can someone help me with this please
never [62]

Answer: B. 1:2

Explanation: Beryllium and chlorine forms a binary ionic compound. Ionic compound is formed when a metal loses its electrons to a receiving non metal. Beryllium (metal) has two valence electrons while chlorine (nonmetal) has seven valence electrons, and so a beryllium atom has to give out its two valence electrons to attain a duplet stable structure while a chlorine atom will gain one electron to attain its stable octet structure. In the reaction between beryllium and chlorine, two atoms of chlorine have to accept the two electrons from one beryllium atom to attain their stable octet structure.

The formula of the compound formed is BeCl2.

3 0
4 years ago
What is the role of neutrons in an atom??
Colt1911 [192]
They're only found in the nucleus and play an important role in keeping the atom stable because they carry a negative charge to counteract the proton's positive charge. 
7 0
3 years ago
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