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azamat
2 years ago
15

?cobalt has a density of 8.90 g. what volume would 17.8 g of Cobalt occupy?

Chemistry
1 answer:
Airida [17]2 years ago
5 0

Answer:

Explanation:

Given parameters:

Density of cobalt = 8.9gcm⁻³

Mass of cobalt = 17.8g

Solution

Density can be defined as the mass per unit volume of a substance:

                      Density = \frac{mass in g}{volume in cm^{3} }

The unknown in the problem is Volume:

                    Volume = \frac{mass}{Density}

                     Volume =   \frac{17.8}{8.9} = 2cm³

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3 years ago
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Calculate the solubility of Mg(OH)2 in water at 25 C. You'll find Ksp data in the ALEKS Data tab. Round your answer to significa
elena-s [515]

Answer:

1.12 × 10⁻⁴ M

Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

       Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

I                                0                    0

C                              +S                +2S

E                                S                  2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

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8 0
2 years ago
An acid is any substance that
ehidna [41]

Answer:

C

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4 0
2 years ago
What is the wavelength of a photon with an energy of 3.50 x 10^-19 J ?
Leokris [45]

Answer:

λ = 5.68×10⁻⁷ m

Explanation:

Given data:

Energy of photon = 3.50 ×10⁻¹⁹ J

Wavelength of photon = ?

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E = hc/λ

h = planck's constant = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

Now we will put the values in formula.

3.50 ×10⁻¹⁹ J =  6.63×10⁻³⁴ Js × 3×10⁸ m/s/ λ

λ =  6.63×10⁻³⁴ Js × 3×10⁸ m/s / 3.50 ×10⁻¹⁹ J

λ =  19.89×10⁻²⁶ J.m / 3.50 ×10⁻¹⁹ J

λ = 5.68×10⁻⁷ m

8 0
2 years ago
5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu?
ale4655 [162]

Answer:

100 J of energy are needed to heat the copper from 20∘C to 80∘C .

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