Question

What is the density in g/L of gas with a molar mass of 2.016 g/mol at 4.77 atm and 118k?

Answer 1

Answer:

0.9926 g/L is the density of gas.

Explanation:

Molar mass of gas = M = 2.016 g/mol

Mass of  gas = m

Density of the gas = d =$\frac{Mass}{Volume}=\frac{m}{V}$...(1)

Pressure of the gas = 4.77 atm

Temperature of the gas = T = 118 K

$PV=nRT=\frac{m}{M}RT$

$P=\frac{m}{V\times M}RT$

$\frac{P\times M}{RT}=d$..(From (1))

$d=\frac{4.77 atm\times 2.016 g/mol}{0.0821 atm l/mol K\times 118 K}$

d = 0.9926 g/L

0.9926 g/L is the density of gas.

Answer 2

n / V = P / RT = (4.77 atm) / ((0.08205746 L atm/K mol) x (118 K)) = 0.4926 mol/L

(2.016 g/mol) x (0.4926 mol/L) = 0.993 g/L