Oxidation state for C in CO
1 answer:
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Answer: Ozone's molecular geometry can be described as bent.
Explanation:
The molecular geometry of the O3 groups has a trigonal planar arrangement.
Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.
Examining the Lewis structure of O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.
Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.
As a result they will be pushed down giving the 03 molecule a bent molecular geometry or shape.
The 03 bond angle will be 116° degrees since it has a Bent molecular geometry
Answer : The order of reaction with respect to A is, second order reaction.
The order of reaction with respect to B is, zero order reaction.
The order of reaction with respect to C is, first order reaction.
Explanation :
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to A
b = order with respect to B
c = order with respect to C
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 1 from 2, we get:
Dividing 1 from 3, we get:
Dividing 3 from 4, we get:
Thus, the rate law becomes:
Thus,
The order of reaction with respect to A is, second order reaction.
The order of reaction with respect to B is, zero order reaction.
The order of reaction with respect to C is, first order reaction.