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Georgia [21]
3 years ago
9

Helpppppppppppppppppppppppppppp

Chemistry
1 answer:
lana66690 [7]3 years ago
5 0
Your answer is:

A volcano spewing out smoke and gases

__________________________

When volcano erupts, various kinds of substances comes out from the interior of earth. A large amount of gases and smoke also come out and enter into atmosphere. These can adversely affect the weather of the area and lead to many health problems.
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Why is there day and night
Burka [1]
Because the moon orbits the earth and when the moon gets in front of the sun it blocks the sunlight and then it becomes night
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3 years ago
Which statement best describes insoluble substances?
Maksim231197 [3]

Answer:

Water does not remain when an insoluble substance is added

7 0
3 years ago
Read 2 more answers
Completely reacting 150.0 g of a substance with oxygen releases 395.1 J of energy. How much energy would be released if 450.0 g
MrMuchimi
To solve this problem we just need to use the rule of three:
150g..................395.1J
450g................xJ

x = 450*395.1/150 = 1185,3J

450.0 g of the substance completely reacted with oxygen will produce 1.1853 kJ(<span>kiloJoule</span>)
4 0
3 years ago
Read 2 more answers
Helpppp pleaseee ill give brainliest
Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

5 0
2 years ago
Complete the equation for respiration: Oxygen + ________ ---&gt; carbon dioxide + energy + water *
Tom [10]

Answer:Sunlight

Explanation:

5 0
3 years ago
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