Question

6x − y + z = −3 4x − 3z = −13 2y + 5z = 15 Find the solutions?

Answer 1

Answer:

The solution of the equation are x = - 1 , y = 0 and z = 3

Step-by-step explanation:

Given three linear equation as :

6 x - y + z = - 3        ......A

4 x - 3 z = - 13           ......B

2 y + 5 z = 15            ......C

Solving eq A and C

I.e 2× (6 x - y + z ) = -3 ×2

or, 12 x - 2 y + 2 z = - 6

So, ( 12 x - 2 y + 2 z ) + ( 2 y + 5 z) = - 6 + 15

Or,  12 x + 7 z = 9         ......D

Solving eq B and D

I.e 3 × ( 4 x - 3 z ) = - 13 × 3

or, 12 x - 9 z = - 39

So, (   12 x + 7 z ) - ( 12 x - 9 z ) = 9 + 39

or,  16 z = 48

∴   z = $\frac{48}{16}$

i.e  z = 3

put the value of z in eq D

So, 12 x + 7×3 = 9  

Or, 12 x = 9 - 21

or,  12 x = - 12

∴   x = -  $\frac{12}{12}$

I.e  x = - 1

Now, Put The value of z in eq C

or, 2 y + 5 z = 15    

or,  2 y + 5 × 3 = 15

Or,  2 y = 15 - 15

or,  2 y = 0  

∴  y = 0

Hence The solution of the equation are x = - 1 , y = 0 and z = 3  Answer